In <[EMAIL PROTECTED]>, Florian
Lindner wrote:
> Hello,
> how can I get the path of a class. I managed to do it with
>
> c.__module__ + "." + c.__name__
>
> but I'm sure there is a better way.
How about using the `inspect` module::
In [33]: import inspect, zipfile
In [34]: inspect.getsource
Florian Lindner wrote:
> Hello,
> how can I get the path of a class. I managed to do it with
>
> c.__module__ + "." + c.__name__
>
> but I'm sure there is a better way.
Please define what you mean by "path" (and how you hope to make use of
this information).
Generally a module has a "path" (i.
Hello,
how can I get the path of a class. I managed to do it with
c.__module__ + "." + c.__name__
but I'm sure there is a better way.
Thanks,
Florian
--
http://mail.python.org/mailman/listinfo/python-list
