Le 02/04/2011 00:42, Ian Kelly a écrit :
You could use a look-ahead assertion with a captured group:
regexp = r'\b(?P\w+)\b(?=.+\b(?P=dup)\b)'
c = re.compile(regexp, re.IGNORECASE | re.DOTALL)
c.findall(text)
It works fine, lookahead assertions in action is what exatly i was
looking for, ma
On Fri, Apr 1, 2011 at 2:54 PM, candide wrote:
> Another question relative to regular expressions.
>
> How to extract all word duplicates in a given text by use of regular
> expression methods ? To make the question concrete, if the text is
>
> --
> Now is better than never.
> Alt
Another question relative to regular expressions.
How to extract all word duplicates in a given text by use of regular
expression methods ? To make the question concrete, if the text is
--
Now is better than never.
Although never is often better than *right* now.
-
