Oh yes indeed!
Now that works :D
Thanks a lot !!
2009/8/3 Kushal Kumaran
>
> On Mon, Aug 3, 2009 at 8:47 PM, Sandhya
> Prabhakaran wrote:
> > Hi,
> >
> > I have a string as str='123ACTGAAC'.
> >
> > I need to extract the numeric part from the alphabetic part which I
> > did using
>
Sandhya Prabhakaran wrote:
> I have a string as str='123ACTGAAC'.
You shouldn't use 'str' as a label like that, it prevents you from
using the str() function in the same body of code.
> How do I blank out the initial numeric part so as to get just the
> alphabetic part. The string is always in t
On Mon, Aug 3, 2009 at 8:47 PM, Sandhya
Prabhakaran wrote:
> Hi,
>
> I have a string as str='123ACTGAAC'.
>
> I need to extract the numeric part from the alphabetic part which I
> did using
numer=re.findall(r'\d+',str)
numer
> 123
>
The docs for re.findall say that it returns a list of mat
Sandhya Prabhakaran wrote:
Hi,
I have a string as str='123ACTGAAC'.
I need to extract the numeric part from the alphabetic part which I
did using
numer=re.findall(r'\d+',str)
numer
123
[snip]
I get:
['123']
which is a _list_ of the strings found.
--
http://mail.python.org/mailman/listinf
Sandhya Prabhakaran writes:
> Hi,
>
> I have a string as str='123ACTGAAC'.
>
> I need to extract the numeric part from the alphabetic part which I
> did using
numer=re.findall(r'\d+',str)
numer
> 123
>
> To get the alphabetic part, I could do
alpha=str.replace('123','')
alpha
> AC
> Hi,
>
> I have a string as str='123ACTGAAC'.
>
> I need to extract the numeric part from the alphabetic part which I
> did using
> >>>numer=re.findall(r'\d+',str)
> >>>numer
> 123
>
> To get the alphabetic part, I could do
> >>>alpha=str.replace('123','')
> >>>alpha
> ACTGAAC
> But when I giv
Hi,
I have a string as str='123ACTGAAC'.
I need to extract the numeric part from the alphabetic part which I
did using
>>>numer=re.findall(r'\d+',str)
>>>numer
123
To get the alphabetic part, I could do
>>>alpha=str.replace('123','')
>>>alpha
ACTGAAC
But when I give
>>>alpha=str.replace(numer,''
