"Adam W." <[EMAIL PROTECTED]> writes:
> I am using the xml.sax package, and I'm running into a little
> problem. When I use the parse(url, ContentHandler()) method, I don't
> know what parse() is naming the instance of ContentHandler.
I'm not sure what you're asking. Why do you need to know the
On Feb 17, 6:12 pm, "Diez B. Roggisch" <[EMAIL PROTECTED]> wrote:
> It's a bit hard to get what you are after, but maybe this solves your
> problem?
>
> handler = FeedHandler()
>
> parse(handler)
>
> print handler.my_instance_variable_of_choice
>
> The above assumes that my_instance_variable_of_cho
Adam W. schrieb:
> I am using the xml.sax package, and I'm running into a little
> problem. When I use the parse(url, ContentHandler()) method, I don't
> know what parse() is naming the instance of ContentHandler.
>
> I have a sub-class of ContentHandler make a dictionary of what it
> parses, but
I am using the xml.sax package, and I'm running into a little
problem. When I use the parse(url, ContentHandler()) method, I don't
know what parse() is naming the instance of ContentHandler.
I have a sub-class of ContentHandler make a dictionary of what it
parses, but the problem is I don't know
