On 7/3/2012 1:03 AM, Steven D'Aprano wrote:
You can create instances without a __dict__ by setting __slots__:
Each *instance* does not have its own dict because each would be equal,
therefore only one hidden mapping is needed, somewhere. But attribute
names must be mapped to objects somehow.
In article ,
Duncan Booth wrote:
> Also you cannot create a subclass of 'type' with non-empty slots (it throws
> a type error "nonempty __slots__ not supported for subtype of 'type'").
> However I don't think that's really relevant as even if they did allow you
> to use __slots__ it wouldn't
Steven D'Aprano wrote:
> You can create instances without a __dict__ by setting __slots__:
That is a necessary but not a sufficient condition. An instance of a class
can be created without a dict only if (either you set __slots__ or you
implement it in C without a __dict__ attribute) AND none
On Jul 3, 3:03 pm, Steven D'Aprano wrote:
> I don't have a use-case for this. But I have some code which assumes that
> every class will have a __dict__, and I wonder whether that is a safe
> assumption.
Remember the recent thread on using a different implementation for
.__dict__?
https://groups.
You can create instances without a __dict__ by setting __slots__:
py> class Dictless:
... __slots__ = ['a', 'b', 'c']
...
py> Dictless().__dict__
Traceback (most recent call last):
File "", line 1, in
AttributeError: 'Dictless' object has no attribute '__dict__'
But the class itself stil
