arghh.
Thanks for removing my blindness :)
-stefan-
On Thu, 18 Jan 2007 10:38:35 +, Roberto Bonvallet wrote:
> Stefan Palme wrote:
>>> using the "re" module of Python (2.3 and 2.4), I tried the following:
>>>
>>> import re
>>> print re.sub('X.*?Y', 'Z', 'Xab\ncdY', re.DOTALL)
>>>
>> Jus
Stefan Palme wrote:
>> using the "re" module of Python (2.3 and 2.4), I tried the following:
>>
>> import re
>> print re.sub('X.*?Y', 'Z', 'Xab\ncdY', re.DOTALL)
>>
> Just noticed, that it works when *compiling* the pattern:
>
> import re
> p = re.compile('X.*?Y', re.DOTALL)
> print re.su
Just noticed, that it works when *compiling* the pattern:
import re
p = re.compile('X.*?Y', re.DOTALL)
print re.sub(p, 'Z', 'Xab\ncdY')
Still the question - my fault or a bug?
Best regards
-stefan-
On Thu, 18 Jan 2007 11:10:08 +0100, Stefan Palme wrote:
>
> Hi all,
>
> using the "re"
Hi all,
using the "re" module of Python (2.3 and 2.4), I tried the following:
import re
print re.sub('X.*?Y', 'Z', 'Xab\ncdY', re.DOTALL)
I wanted to replace
Xab
cdY
by a single "Z", but the "." in the pattern does not match the
included "\n".
When using the pattern "X(.|\n)*?Y" (ex
