Thank you very much. I understand that
Regards,
Mahmood
On Friday, May 26, 2017 5:01 AM, Cameron Simpson wrote:
On 25May2017 20:37, Mahmood Naderan wrote:
>Cameron, thanks for the points. In fact the file name contains multiple '_'
>characters. So, I appreciate what you recommended.
>
>
On 25May2017 20:37, Mahmood Naderan wrote:
Cameron, thanks for the points. In fact the file name contains multiple '_'
characters. So, I appreciate what you recommended.
filenames = {}
for name in glob.glob('*chunk_*'):
left, right = name.rsplit('_', 1)
if left.endswith('chunk') and ri
Hi guys,
Cameron, thanks for the points. In fact the file name contains multiple '_'
characters. So, I appreciate what you recommended.
filenames = {}
for name in glob.glob('*chunk_*'):
left, right = name.rsplit('_', 1)
if left.endswith('chunk') and right.isdigit():
fi
bartc wrote:
> On 24/05/2017 16:41, Peter Otten wrote:
>> Dennis Lee Bieber wrote:
>>
>>> On Tue, 23 May 2017 21:42:45 +0100, bartc declaimed the
>>> following:
>>>
Is it necessary to sort them? If XXX is known, then presumably the
first file will be called XXX_chunk_0, the next XXX_chu
On 24/05/2017 16:41, Peter Otten wrote:
Dennis Lee Bieber wrote:
On Tue, 23 May 2017 21:42:45 +0100, bartc declaimed the
following:
Is it necessary to sort them? If XXX is known, then presumably the first
file will be called XXX_chunk_0, the next XXX_chunk_1 and so on.
XXX_chunk_1
XXX_chu
Dennis Lee Bieber wrote:
> On Tue, 23 May 2017 21:42:45 +0100, bartc declaimed the
> following:
>
>>Is it necessary to sort them? If XXX is known, then presumably the first
>>file will be called XXX_chunk_0, the next XXX_chunk_1 and so on.
>>
>
> XXX_chunk_1
> XXX_chunk_10
> XXX_chunk_2
This i
On Tuesday, May 23, 2017 at 8:29:57 PM UTC+1, Mahmood Naderan wrote:
> Hi,
> There are some text files ending with _chunk_i where 'i' is an integer. For
> example,
>
> XXX_chunk_0
> XXX_chunk_1
> ...
>
> I want to concatenate them in order. Thing is that the total number of files
> may be varia
On 2017-05-23 13:38, woo...@gmail.com wrote:
> It is very straight forward; split on "_", create a new list of
> lists that contains a sublist of [file ending as an integer, file
> name], and sort
>
> fnames=["XXX_chunk_0",
> "XXX_chunk_10",
> "XXX_chunk_1",
>
On 23May2017 21:14, Mahmood Naderan wrote:
OK guys thank you very much. It is better to sort them first.
Here is what I wrote
files = glob.glob('*chunk*')
I'd be inclined to go with either '*chunk_*' or just to read the strings from
os.listdir, because what you want isn't easily written as
On 23/05/17 22:14, Mahmood Naderan via Python-list wrote:
sorted=[[int(name.split("_")[-1]), name] for name in files]
This isn't sorting anything. At no point do you invoke a sort operation.
It's processing the list in the original order and generating a new list
with a different format but *
On 2017-05-23 22:14, Mahmood Naderan via Python-list wrote:
OK guys thank you very much. It is better to sort them first.
Here is what I wrote
files = glob.glob('*chunk*')
Here you're making a list of (index, name) pairs:
sorted=[[int(name.split("_")[-1]), name] for name in files]
but y
OK guys thank you very much. It is better to sort them first.
Here is what I wrote
files = glob.glob('*chunk*')
sorted=[[int(name.split("_")[-1]), name] for name in files]
with open('final.txt', 'w') as outf:
for fname in sorted:
with open(fname[1]) as inf:
for line in
On 2017-05-23 19:29, Mahmood Naderan via Python-list wrote:
> There are some text files ending with _chunk_i where 'i' is an
> integer. For example,
>
> XXX_chunk_0
> XXX_chunk_1
> ...
>
> I want to concatenate them in order. Thing is that the total number
> of files may be variable. Therefore, I
On 23/05/2017 20:55, Rob Gaddi wrote:
Yup. Make a list of all the file names, write a key function that
extracts the numbery bits, sort the list based on that key function, and
go to town.
Is it necessary to sort them? If XXX is known, then presumably the first
file will be called XXX_chunk_
It is very straight forward; split on "_", create a new list of lists that
contains a sublist of [file ending as an integer, file name], and sort
fnames=["XXX_chunk_0",
"XXX_chunk_10",
"XXX_chunk_1",
"XXX_chunk_20",
"XXX_chunk_2"]
sorted_lis
On 2017-05-23 21:16, Mahmood Naderan via Python-list wrote:
Yup. Make a list of all the file names, write a key function that
extracts the numbery bits, sort the list based on that key function, and
go to town.
Alternatively, when you create the files in the first place, make sure
to use mor
On 2017-05-23, Mahmood Naderan via Python-list wrote:
> import glob;
> for f in glob.glob('*chunk*'):
> print(f)
>
> it will print in order. Is that really sorted or it is not guaranteed?
https://docs.python.org/2/library/glob.html
https://docs.python.org/3/library/glob.html
It's in the f
>Yup. Make a list of all the file names, write a key function that
>extracts the numbery bits, sort the list based on that key function, and
>go to town.
>
>Alternatively, when you create the files in the first place, make sure
>to use more leading zeros than you could possibly need.
>xxx_chun
On 05/23/2017 12:37 PM, breamore...@gmail.com wrote:
On Tuesday, May 23, 2017 at 8:29:57 PM UTC+1, Mahmood Naderan wrote:
Hi,
There are some text files ending with _chunk_i where 'i' is an integer. For
example,
XXX_chunk_0
XXX_chunk_1
...
I want to concatenate them in order. Thing is that the
Hi,
There are some text files ending with _chunk_i where 'i' is an integer. For
example,
XXX_chunk_0
XXX_chunk_1
...
I want to concatenate them in order. Thing is that the total number of files
may be variable. Therefore, I can not specify the number in my python script.
It has to be "for all
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