Daniel wrote:
> Hi Kent
>
> This isn't work with the following line:
> FieldGraphic56::= GraphicString EBCDIC BC= " " SIZE (56
> BYTES)
>
>
byter = re.compile(r'SIZE \((\d+) BYTE\)')
Because the string doesn't match the pattern, can you see the difference? Do
you understand what
Hi Kent
This isn't work with the following line:
FieldGraphic56::= GraphicString EBCDIC BC= " " SIZE (56
BYTES)
>>> byter = re.compile(r'SIZE \((\d+) BYTE\)')
>>> s = 'SIZE (1 BYTE)'
>>> byter.sub(r'SIZE(\1)', s)
'SIZE(1)'
>>> byter.sub(r'SIZE(\1)', line)
'FieldGraphic56::= Gr
Hi Kent
This isn't work with the following line:
FieldGraphic56::= GraphicString EBCDIC BC= " " SIZE (56
BYTES)
>>> byter = re.compile(r'SIZE \((\d+) BYTE\)')
>>> s = 'SIZE (1 BYTE)'
>>> byter.sub(r'SIZE(\1)', s)
'SIZE(1)'
>>> byter.sub(r'SIZE(\1)', line)
'FieldGraphic56::= Gr
Daniel wrote:
> I need match a regular expression, change it erasing the other strings
> after this. Just like:
>
> a = "I'm going send to out of space, find another race"
>
> And I want to match "space" instance, and erase the other.
If you mean you want to get rid of everything after 'space',
Hi Kent
Thanks for your help, it worked sucessfully. I have another question, I
think it is a stupid and simple but...
I need match a regular expression, change it erasing the other strings
after this. Just like:
a = "I'm going send to out of space, find another race"
And I want to match "space
Daniel wrote:
> Hello all
>
> I need to build a program that check the sintax in a line:
>
> SIZE (1 BYTE)
>
> and change the correct number of bytes to the following format:
>
> SIZE(1)
>
> without the "BYTE" word. But, the number of bytes can be over 3 digits,
> and the entitie can't have sp
Hello all
I need to build a program that check the sintax in a line:
SIZE (1 BYTE)
and change the correct number of bytes to the following format:
SIZE(1)
without the "BYTE" word. But, the number of bytes can be over 3 digits,
and the entitie can't have spaces but the correct number of bytes i
