I am currently using the following technic to get the info above:
all = defaultdict(int)
hosts = defaultdict(int)
filename = defaultdict(int)
for r in log:
all[r['host'],r['file']] += 1
hosts[r['host']] += 1
filename[r['file']] = 1
for host in sorted(hosts,key=hosts.get, reverse=True):
On Wed, Oct 8, 2008 at 1:55 PM, Joe Python <[EMAIL PROTECTED]> wrote:
> I want to find the top '100' hosts (sorted in descending order of total
> requests) like follows:
> Is there a fast way to this without scanning the log file many times?
As you encounter a new "host" add it to a dict (or anoth
I have a written a generator for an apache log which returns two types of
information,
hostname and the filename requested.
The 'log' generator can be 'consumed' like this:
for r in log:
print r['host'], r['filename']
I want to find the top '100' hosts (sorted in descending order of total
requ
