On 31/05/2006 7:20 PM, Bo Yang wrote:
> I am sorry , and thanks for your friendliness .
> I have change my source code for more meaningful variable name and more
> comments follow the instructions
> John has writen . I think that is useful for you to look my code .
>
> And this time I put the cod
Le Mercredi 31 Mai 2006 08:58, Bo Yang a écrit :
> RuntimeError: maximum recursion depth exceeded
It's tied to the recursive call to the ring function, python raises a limit to
recursive calls to avoid infinite recursion.
You can just adjust the limit using these two lines when you call the functi
I am sorry , and thanks for your friendliness .
I have change my source code for more meaningful variable name and more
comments follow the instructions
John has writen . I think that is useful for you to look my code .
And this time I put the code in the attachment . Indeed , I write that
in
I am sorry , and thanks for your friendliness .
I have change my source code for more meaningful variable name and more
comments follow the instructions
John has writen . I think that is useful for you to look my code .
And this time I put the code in the attachment . Indeed , I write that
in th
On 31/05/2006 4:58 PM, Bo Yang wrote:
> Hi ,
> I have writen a python program to slove a problem described as below:
>
> (Forgive my poor English !)
>
> Put the 2^n 0 or 1 to form a ring ,
Sorry, I can't understand that. It would be very helpful if you wrote
out (for example, when n == 3) what t
Bo Yang enlightened us with:
> I have writen a python program to slove a problem described as
> below:
Please post again, but then leaving indentation intact, since this is
unreadable.
Sybren
--
The problem with the world is stupidity. Not saying there should be a
capital punishment for stupidit
Hi ,
I have writen a python program to slove a problem described as below:
(Forgive my poor English !)
Put the 2^n 0 or 1 to form a ring , and we can select any continuous n
ones from
the ring to constitute a binary number . And obviously we can get 2^n
selections ,
so the question is :
Given a n
