On 27 February 2016 at 16:50, Ganesh Pal wrote:
> Iam on python 2.6 and Linux , I need input on the below program ,
> here is the spinet of my program
It would be much better if you presented a complete program here.
Otherwise the missing parts will confuse people. See:
http://sscce.org/
> file
On Sun, 28 Feb 2016 03:50 am, Ganesh Pal wrote:
> Iam on python 2.6 and Linux , I need input on the below program ,
> here is the spinet of my program
>
>
> filename='/tmp2/2.txt'
>
> def check_file():
> """
> Run the command parallel on all the machines , if there is a
> file named /
>>
> what is run(...)
>
The run (_ is a wrapper it uses suprocess.Popen and returns stdout
,error and extitcod e
> not a good idea to have catchall exception
how to fix this ?
>
>> > return False
>> > if __name__ == '__main__':
>> > main()
>> >
>> --
>>
> copy and paste your tr
On Sat, Feb 27, 2016 at 12:01 PM, Ganesh Pal wrote:
> changed baddr="" to file ="" in the example program , sorry for the typo
>
> > filename='/tmp2/2.txt'
> >
> > def check_file():
>
don't use global filename. just pass filename into check_file
def check_file(filename):
> > """
> > R
changed baddr="" to file ="" in the example program , sorry for the typo
> filename='/tmp2/2.txt'
>
> def check_file():
> """
> Run the command parallel on all the machines , if there is a
> file named /tmp/file2.txt extract file2.txt
>
> """
> global filename
> file = ''
>
Iam on python 2.6 and Linux , I need input on the below program ,
here is the spinet of my program
filename='/tmp2/2.txt'
def check_file():
"""
Run the command parallel on all the machines , if there is a
file named /tmp/file2.txt extract file2.txt
"""
global filename
bad
On 9/25/2010 3:53 AM, deluxstar wrote:
The traceback is:
2010-09-25 10:50:38+0300 [-] Traceback (most recent call last):
2010-09-25 10:50:38+0300 [-] File "../appsrv/lqcommon.py", line 983,
in getPRMS
2010-09-25 10:50:38+0300 [-] File "/usr/lib/python2.6/inspect.py",
line 931, in getouterfra
On Samstag 25 September 2010, Steven D'Aprano wrote:
> My guess is that you've copied the .pyc file onto the server,
> BUT there is also an older version of the .py file there as
> well. Because the modification date is older than that of the
> .pyc file, Python executes the compiled code from the
On Sat, 25 Sep 2010 00:53:13 -0700, deluxstar wrote:
> The traceback is:
> 2010-09-25 10:50:38+0300 [-] Traceback (most recent call last):
> 2010-09-25 10:50:38+0300 [-] File "../appsrv/lqcommon.py", line 983,
> in getPRMS
> 2010-09-25 10:50:38+0300 [-] File "/usr/lib/python2.6/inspect.py",
>
e code works on local development environment both on linux
> > and windows. When checked in to production environment,
> > inspect.currentframe() or inspect.stack() function gives "List index
> > out of range error".
>
> > When I googled, I found only one clue o
ect.currentframe() or inspect.stack() function gives "List index
> out of range error".
>
> When I googled, I found only one clue of copying pyc files:
> http://forum.webfaction.com/viewtopic.php?pid=16808
>
> Why inspect modules gives this error? OR Is there another wa
= inspect.getouterframes(curframe, 2)
calframe[1][0].f_locals['variable']
This sample code works on local development environment both on linux
and windows. When checked in to production environment,
inspect.currentframe() or inspect.stack() function gives "List index
out of range error".
Whe
sam wrote:
I gues: no_lines=len(list_initial)
> for j in range(0, no_lines):
range returns 0, 1, 2, ..., no_lines-1
>
> k = 0
> while k < no_lines:
> sorted_check = 0
> if list_initial[k] < list_initial[k+1]:
When j gets its last value (no_lines-1) k has the same va
gabriel,
> Now that your main problem is gone, just a few comments:
> - python lists know their length, so you don't need explicit no_lines
> and no_lines_2
> - list_initial.remove(temp_str) is fairly slow - it has to *scan* the
> list to locate temp_str. Just keep its index instead, and use del
>
At Wednesday 20/9/2006 19:39, sam wrote:
thanks again for your help. that sorted out something that had really
been bugging me.
Now that your main problem is gone, just a few comments:
- python lists know their length, so you don't need explicit no_lines
and no_lines_2
- list_initial.remove(t
"sam" <[EMAIL PROTECTED]> writes:
> hey everybody, this is my first time posting here. i'm pretty new to
> python and programming in general (as you'll soon work out for
> yourselves...)
On behalf of the entire Python community, *thank you* for putting this
disclaimer only in the body of your mes
for what it's worth. and it is approx. five times quicker than the
bubblesort i wrote to begin with on a 286-word highly unordered list,
so i wasn't wasting my time after all...
__
import time
file_input = open('wordlist.txt', 'r
yes, yes, of course, thank you. not sure what i thought i was doing
there.
i'll see if i can get it running now...
--
http://mail.python.org/mailman/listinfo/python-list
; list_initial[k+1]:
> temp_str = list_initial[k+1]
> sorted_check = 1
> k += 1
>
> list_initial.remove(temp_str)
> list_final.append(temp_str)
> no_lines -= 1
>
> if sorted_check == 0:
> break
>
> problem
actually, that little bit of code i wrote is obscenely wrong anyway, so
please don't bother analyzing the flow.
any insight into the "list index out of range" error would still be
welcome, though.
--
http://mail.python.org/mailman/listinfo/python-list
itial[k]
elif list_initial[k] > list_initial[k+1]:
temp_str = list_initial[k+1]
sorted_check = 1
k += 1
list_initial.remove(temp_str)
list_final.append(temp_str)
no_lines -= 1
if sorted_check == 0:
break
problem is, i keep gett
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