jesus, now i fixed it, using odd lambda sort.
l.sort(lambda x,y: cmp(len(x), len(y)))
print l
BUT I AM STILL CONFUSED WHY COSTOMIZED SORT FAILED TO SORT AS IT IS
PROGRAMMER!
thinke365 wrote:
>
> i mean the output i want is:
> [ [1, 2], [1, 2, 3, 4], [1, 2, 3, 4, 5]], that is sort
i mean the output i want is:
[ [1, 2], [1, 2, 3, 4], [1, 2, 3, 4, 5]], that is sort according to the
length of the list element
thinke365 wrote:
>
> l = list()
> l1 = list((1, 2, 3, 4))
> l2 = list((1,2))
> l3 = list((1, 2, 3, 4, 5))
> l.append(l1)
> l.append(l2)
>
l = list()
l1 = list((1, 2, 3, 4))
l2 = list((1,2))
l3 = list((1, 2, 3, 4, 5))
l.append(l1)
l.append(l2)
l.append(l3)
print l
def sort_by_list(E1, E2):
print len(E1), len(E2)
return len(list(E1)) > len(list(E2))
l.sort(cmp=sort_by_list)
print l
output:
[[1, 2, 3, 4], [1, 2], [1, 2, 3, 4
Bugzilla from ra.ravi@gmail.com wrote:
>
> On Jan 23, 10:37 pm, thinke365 wrote:
>> such as uniform distribution, Normal distribution or poisson
>> distribution.
>> is there any package that can be used to generate such random numbers.
>>
>> --
>
such as uniform distribution, Normal distribution or poisson distribution.
is there any package that can be used to generate such random numbers.
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Sent
for example, i may define a python class:
class A:
def sayHello():
print 'hello'
a = A()
a.attr1 = 'hello'
a.attr2 = 'bb'
b = A()
a.attr2 = 'aa'
how can i know whether an object have an attribute named attr1?
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