> > > resultname="""
> > > That starts a string literal.
>
> i am not sure if this is the right way..i used it in case
> matchdistance < threshold return False.then the filename will not be
> taken from the filenameslist and so returns as an empty string.
>a one-tuple
why not use None instea
> If the string is only used to open a file, and never shown to the user,
> what you prefer is irrelevant, isn't it?
guess thats right..
> Back to your code, try this:
>
> from os.path import join, normpath
> folder = 'F:/brown/code/python/fgrp1'
> names = ['amber1.jpg', 'amber3.jpg', 'amy1.jpg
hi
i am using python on WinXP..i have a string 'folder ' that i want to
join to a set of imagefile names to create complete qualified names so
that i can create objects out of them
folder='F:/brown/code/python/fgrp1'
filenms=['amber1.jpg', 'amber3.jpg', 'amy1.jpg', 'amy2.jpg']
filenameslist=[]
for
also
if i were to write unit test for this method ,how shd i do it? shd i
be checking all values in the matrix created inside and so on?
gordon
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hi
i am writing code to check a folder containing images and then process
thir vals using PIL and do some calc to create a matrix of values .if
the folder has any new imgs added the program will do all calc again
and dump the values into a cachefile.If the folder contents remain
unaltered the progr
sorry..the last post didn't appear!
> Are you sure? What happens if the vector with the smallest
> sum(distance) is the first one?
>
initially i will set imgindex =0 so if the first one is of smallest
sum..,the image will be reteived by imgindex 0
> (a) Can't you replace the inner loop with
>
> 1. 'temp' is not used
> 2. Lose the superfluous parentheses in 'if' statements
> 3. Put space around operators
> 4. I've never used any of numpy & friends, but:
> (a) Can't you replace the inner loop with something like this:
>distance = abs(input_weight - weights[image, :])
> (b) I doubt
hi
i am using python to do some image data calculations..I use the
following numpy.ndarrays ,(i have given their shapes and ranks)
weights=ndarray :shape(100,30),ndim=2 will have vals like
2458121847.49 (of type 'numpy.float64')
input_weight=ndarray :shape(30,),ndim=1 (similar to above but diff
if this is too silly a qn pls forgive
I was learning numpy.ndarrays thru the tutorial.
myarr=numpy.array( [ [10, 20, 30, 40],[1,2,3,4],[5,6,7,8] ] )
if i want to access the element 3 i can do it by myarr[1, 2]
but then myarr[1][2] will also give the same result..is there any
reason why two types
