On Nov 11, 2:25 pm, John Gordon wrote:
> In <8f5215a8-d08f-4355-a5a2-77fcaa32c...@j10g2000vbe.googlegroups.com> macm
> writes:
>
> > I pass a nested dictionary to a function.
> > def Dicty( dict[k1][k2] ):
>
> That's not valid syntax.
>
> > p
Ok Sorry!!
Sorry the noise!!
def func(object):
print "%s" % object
Regards
On Nov 11, 2:33 pm, macm wrote:
> Hi
>
> Sorry ! My mistake.
>
> >>> myDict = {}
> >>> myDict['foo'] = {}
> >>> myDict['foo']['
'bar'])
... # I want inspect this MyObj
... # what keys was pass
... print MyObj.keys() ## WRONG
... # So What I want is :
... # return foo bar
>>> result = myFunction( myDict['foo']['bar'] )
>>> result
Should
On Mar 21, 9:31 am, Robert wrote:
> Can I install Python 2.7 and 3.2 (from python.org) side by side on OSX
> without them stepping all over each other?
Yes, sure! Look for "python environment"
http://pypi.python.org/pypi/virtualenv
Regards
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Thanks all
In [11]: reps = 5
In [12]: t = Timer("url = 'http://docs.python.org/dev/library/
stdtypes.html? highlight=partition#str.partition' ;sp =
re.compile('(//?|[;?:@=&#.])'); filter(len, sp.split(url))", 'import
re')
In [13]: print sum(t.repeat(repeat=reps, number=1)) / reps
4.94003295898e-0
On Dec 23, 4:57 pm, Hrvoje Niksic wrote:
> I stumbled upon this. Python 2.6:
>
> Python 2.6.6 (r266:84292, Sep 15 2010, 15:52:39)
> [GCC 4.4.5] on linux2
> Type "help", "copyright", "credits" or "license" for more information.>>> 9.95
> 9.9493
> >>> "%.16g" % 9.95
> '9.949
#x27;.','html','?','highlight','=','partition','#','str','.','partition']
re module is slow.
Even I make a loop in urlparse.urlsplit I can lost specialMeaning
order.
Seen easy but best aproach will be rec
Hi Folks
I have this:
url = 'http://docs.python.org/dev/library/stdtypes.html?
highlight=partition#str.partition'
So I want convert to
myList =
['http',':','//','docs','.','python','.','org','/','dev','/','library','/','stdtypes','.','html','?','highlight','=','partition','#','str','.','partiti
Hi Folks
I am trying run Distutils setup inside a script.
The Docs dont tell me much and I cant find any examples.
This script will generate shared libraries recursive to all files in a
dir.
-
import os
import sys
from distutils.core import setup as d
from distutil
m{z}.start()
for x in L:
z=L.index(x)
d1.append(q{z}.get()) # <= So now I am sure that q{z}.get() isn't
lock
print list(d1)
return
I tried use list but didn't work look below one shot.
Best Regards
macm
I tried :
d
sult
[[], [1, 3, '79b'], [2]]
>>>
but should be {'ac': [1, 3, '79b'], 'ab': [2]}
Best Regards
Mario
On 10 nov, 18:14, macm wrote:
> Hi Folks
>
> I am studing yet (with fever, grasp and headache).
>
> I know I can do better, but first
Hi Folks
I am studing yet (with fever, grasp and headache).
I know I can do better, but first I should learn more about
"dictionary comprehension syntax" in python 2.65
>>> dict1 = {'ab':[[1,2,3,'d3','d4',5],12],'ac':[[1,3,'78a','79b'],54],'ad':
>>> [[56,57,58,59],34], 'ax': [[56,57,58,59],34]
Sorry Mr. Nagle and Folks
I had a bad day today.
I need forward but with fever, a grasp and headache is hard.
You are absolute right, I was rude and I ask your pardon.
About my code, sorry I thought was the best way to copy and paste in
python console.
Best Regards
macm
On Nov 9, 7:03 pm
:[2,'d3']} # look last key/value 'ax' (dict1,
dict2) even intersec a key but not values from list so not valid
and difference from dict3
dict3 = {'ac':[[1,3,67,'gf'],12],'at':[[2,4,50,42,'c4'],12],'as':
[[1,3,'79b',45,65,'er4'],54],'ae': [[56,57,58,59],34]}
result from (intersect - dict3)
{'ac':['79b'], 'ab':[2,'d3']}
Thanks in advance!
Before someone blame me.
Yes I am trying learn python Functional Programming! ; )
Best Regards
macm
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http://mail.python.org/mailman/listinfo/python-list
#x27;k5']
>>> ndict = reduce(lambda x,y: {y:x}, reversed(l), {'/':[1,2,3]})
>>> x = l + list('/')
>>> print appendNested(ndict, x, 5)
{'k1': {'k2': {'k3': {'k4': {'k5': {'/': [1, 2, 3, 5]}
Hi Peter
Thanks a lot for your tips and codes,
Cake Recipes are good to learn! So I post just basic issues.
Hopping a good soul like you can help me!
But I am still learning... : )
Best Regards
macm
On 5 nov, 15:40, Peter Otten <__pete...@web.de> wrote:
> macm wrote:
> > t
: [1, 2, 3]}
>>> d['k1']['k2']['k3']['k4']['k5']['/']
[1, 2, 3]
>>>
now I want generate the "index" to access the element.
==> d['k1']['k2']['k3']['k4']['k5'][&
vance.
Best regards
macm
On 4 nov, 16:53, Chris Rebert wrote:
> On Thu, Nov 4, 2010 at 11:48 AM, macm wrote:
> > Hi Folks
>
> > How convert list to nested dictionary?
>
> >>>> l
> > ['k1', 'k2', 'k3', 'k4', '
Hi Folks
How convert list to nested dictionary?
>>> l
['k1', 'k2', 'k3', 'k4', 'k5']
>>> result
{'k1': {'k2': {'k3': {'k4': {'k5': {}}
Regards
macm
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http://mail.python.org/mailman/listinfo/python-list
Peter
Ok! Both works fine!
Thanks a lot!
>>> for v in f(a['a']['b']):
... b.extend(v)
b
Now I will try find which script is the fast!
Regards
macm
On 4 nov, 15:56, macm wrote:
> Hi Folks
>
> Thanks a lot
>
> Script from Diez works:
>
all last):
File "", line 2, in
TypeError: 'int' object is not iterable
I am trying understand this error.
Best Regards and thanks a lot again!
Mario
macm
On 4 nov, 15:26, Peter Otten <__pete...@web.de> wrote:
> macm wrote:
> > How find all childrens
;/': [1,
2, 3, 4], 'bc': {'bcd': {'/': [68, 69, 66]}, '/': [51, 52, 54]}}}
>>> a['a']['b']
{'ba': {'/': [41, 42, 44]}, '/': [1, 2, 3, 4], 'bc': {'bcd': {'/':
[68, 69, 66]}, '/': [51, 52, 54]}}
>>> a['a']['b'].values()
[{'/': [41, 42, 44]}, [1, 2, 3, 4], {'bcd': {'/': [68, 69, 66]}, '/':
[51, 52, 54]}]
Now I want find all values of key "/"
Desire result is [41, 42, 44, 1, 2, 3, 4, 68, 69, 66, 51, 52, 54]
I am trying map, reduce, lambda.
Regards
macm
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http://mail.python.org/mailman/listinfo/python-list
again :
IhaveOtherName = ('some','thing')
myDef(IhaveOtherName)
so what I am looking for in myDef
result = IhaveOtherName
--
Is it possible with python?
Regards
macm
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