On 15 Cze, 01:25, Dave Angel wrote:
> On 01/-10/-28163 02:59 PM, kafooster wrote:
>
> > On 14 Cze, 22:26, MRAB wrote:
>
> >> Multiply the numpy array by a scaling factor, which is
> >> float(max_8bit_value) / float(max_16bit_value).
>
> > could you ple
On 15 Cze, 00:06, MRAB wrote:
>
> Yes. Something like this:
>
> fileobj = open("hand.raw", 'rb')
> data = numpy.fromfile(fileobj, dtype=numpy.uint16)
> fileobj.close()
> data = data * float(0xFF) / float(0x)
> data = numpy.array(data, dtype=numpy.uint8)
> data = data.reshape((96, 470, 352))
>
On 14 Cze, 22:26, MRAB wrote:
>
> Multiply the numpy array by a scaling factor, which is
> float(max_8bit_value) / float(max_16bit_value).
could you please explain it a little? I dont understand it. like
multiplying each element?
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Ok, I solved the problem with matplotlib
fileobj = open("hand.raw", 'rb')
data = numpy.fromfile(fileobj,dtype=np.uint16)
data = numpy.reshape(data,(96,470,352))
imshow(data[:,:,40],cmap='gray')
show()
the error was caused by different order of data, however it still
reads the dataset as half of i
On 13 Cze, 22:52, Wanderer wrote:
> On Jun 13, 4:41 pm, kafooster wrote:
>
> > Wanderer: by *.raw I mean images with .raw extension, pure pixel data
> > without headerhttp://en.wikipedia.org/wiki/Raw_image_format
>
> > That is a clear and nice code however I think I
Wanderer: by *.raw I mean images with .raw extension, pure pixel data
without header
http://en.wikipedia.org/wiki/Raw_image_format
That is a clear and nice code however I think Image.open cannot
handle .raw since i get error
image1 = Image.open("hand.raw", "rb")
File "D:\Python27\lib\site-p
I am working on some medical image data, and I try to look into
specific slice of 3d *.raw image. I know voxels are 16 bit int, and
dimensions are 352*470*96. I checked it in some pro medical image
viewer, it is alright. However, with the code I use, I display just
white noise image.(but worked
