PRC ha scritto:
> Hi folks,
>
> I have a tuple of tuples, in the form--> ((code1, 'string1'),(code2,
> 'string2'),(code3, 'string3'),)
>
> Codes are unique. A dict would probably be the best approach but this
> is beyond my control.
>
> Here is an example:
pets = ((0,'cat'),(1,'dog'),(2,'mo
Steve Holden ha scritto:
>>> What I do not fully understand is the line "self.tasks[:] = tasks".
>>> Why does the guy who coded this did not write it as "self.tasks =
>>> tasks"? What is the use of the "[:]" trick ?
>>
>> It changes the list in-place. If it has been given to other objects,
>> i
Grant Edwards ha scritto:
>> One solution:
>>
> s = '(a, b, "c", d, "e")'
> print [x.strip('" ') for x in s.strip('()').split(',')]
>> ['a', 'b', 'c', 'd', 'e']
>
> That fails when a quoted string contains commas:
>
s = '(a, b, "c", d, "e,f,g")'
print [x.strip('" ') for x in s.
Siah ha scritto:
> Hi,
>
> I need to convert the string: '(a, b, "c", d, "e")' into the following
> list ['a', 'b', 'c', 'd', 'e']. Much like a csv reader does. I usually
> use the split function, but this mini-monster wouldn't properly get
> split up due to those random quotations postgresql retu
Tobiah ha scritto:
> Is there a way to call function in an imported
> module having only the name?
>
>
> func_name = 'doit'
>
> real_func = foo.some_magic(func_name)
>
> #Now call it
> real_func(args)
>
>
> I'm trying to set up a function dispatcher for a
> SOAP server.
>
> Thanks,
>
> Tobi
Georg Brandl ha scritto:
f.func_code.co_flags
> 67
g.func_code.co_flags
> 99
>
> => 32 (CO_GENERATOR in compiler.consts) is the flag that indicates a
> generator code object.
>
> Georg
What a fast reply!
Thank You very much! :-)
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Hi all.
Is there a way to know if a function object is actually a "generator
function" or not ? e.g.:
def f():
pass
def g():
yield None
f.__class__ is the same as g.__class__ , i.e. "function" type.
But i "know" that the second, when invoked, returns a generator object,
becaus
Roberto Bonvallet ha scritto:
> imho <[EMAIL PROTECTED]>:
>> map(lambda x:"" , [i for i in [a,b,c] if i in ("None",None) ])
>
> You don't need map when using list comprehensions:
>
>["" for i in [a, b, c] if i in ("None&quo
[EMAIL PROTECTED] ha scritto:
> hi
> i wish to map None or "None" values to "".
> eg
> a = None
> b = None
> c = "None"
>
> map( , [i for i in [a,b,c] if i in ("None",None) ])
>
> I can't seem to find a way to put all values to "". Can anyone help?
> thanks
>
You already filtered [a,b,c] in
boris ha scritto:
>
> COOL! You just saved me an awful lot of work.
>
> Thanks, Diego!
>
> Boris
>
;-)
Bye
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boris ha scritto:
> I have two directories, lib1 and lib2, that both contain the package
> foo, one with the submodule mod1
> and the other with the submodule mod2:
> [...]
> Now this script:
>
> import sys
> sys.path.append("lib1")
> sys.path.append("lib2")
> import foo.mod1
>
> will find the mo
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