Hi
Have two dict() of the same length and i want print them to a common file.
a={1: 1, 2: 2, 3: 3}
b={1: 11, 2: 22, 3: 33}
in order to obtain
1 1 1 11
2 2 2 22
3 3 3 33
I tried
output = open(dst_file, "w")
for (a), b , (c) , d in a.items() , b.items() :
output.write("%i %i %i %i\n" % (
Hi Ian and MRAB
thanks to you input i have improve the speed of my code. Definitely reading in
dic() is faster. I have one more question.
In the dic() I calculate the sum of the values, but i want count also the
number of observation, in order to calculate the average in the end.
Should i creat
Hi,
I have this script in python that i need to apply for very large arrays (arrays
coming from satellite images).
The script works grate but i would like to speed up the process.
The larger computational time is in the for loop process.
Is there is a way to improve that part?
Should be better
2007/idiomatic/handout.html#use-in-where-possible-1
>>
>> That link doesn't actually discuss dict.{iter}items()
>>
>> Both are O(N) because you have to touch each item in the dict--you
>> can't iterate over N entries in less than O(N) time. For small
&
deas?
>> Thanks in advance
>
> How's this?
>
> from __future__ import print_function
>
> output = open("out.txt", "w")
>
> for (a, b), c in d.items():
> print(a, b, c, file=output)
>
> output.close()
>
> Oscar.
>> --
>> http://mail.python.org/mailman/listinfo/python-list
--
Giuseppe Amatulli
Web: www.spatial-ecology.net
--
http://mail.python.org/mailman/listinfo/python-list
;
> from __future__ import print_function
>
> output = open("out.txt", "w")
>
> for (a, b), c in d.items():
> print(a, b, c, file=output)
>
> output.close()
>
> Oscar.
>> --
>> http://mail.python.org/mailman/listinfo/python-list
--
Giuseppe Amatulli
Web: www.spatial-ecology.net
--
http://mail.python.org/mailman/listinfo/python-list
Hi,
I have a dict() unique
like this
{(4, 5): 1, (5, 4): 1, (4, 4): 2, (2, 3): 1, (4, 3): 2}
and i want to print to a file without the brackets comas and semicolon in order
to obtain something like this?
4 5 1
5 4 1
4 4 2
2 3 1
4 3 2
Any ideas?
Thanks in advance
Giuseppe
--
http://mail.python.o
Terry and MRAB,
thanks for yours suggestions,
in the end i found this solution
mask=( a != 0 ) & ( b != 0 )
a_mask=a[mask]
b_mask=b[mask]
array2D = np.array(zip(a_mask,b_mask))
unique=dict()
for row in array2D :
row = tuple(row)
if row in unique:
unique[row] += 1
else:
Hi,
would like to take eliminate a specific number in an array and its
correspondent in an other array, and vice-versa.
given
a=np.array([1,2,4,4,5,4,1,4,1,1,2,4])
b=np.array([1,2,3,5,4,4,1,3,2,1,3,4])
no_data_a=1
no_data_b=2
a_clean=array([4,4,5,4,4,4])
b_clean=array([3,5,4,4,3,4])
after i
