On Sep 30, 4:18 am, 7stud -- <[EMAIL PROTECTED]> wrote:
> SpringFlowers AutumnMoon wrote:
> > we have no way
> > of knowing what we pass in could get changed.
>
> Sure you do. You look at the function's signature. In order to use
> someone else's library, you have to know the function's signature
I wonder which language allows you to change an argument's value?
like:
foo(&a) {
a = 3
}
n = 1
print n
foo(n) # passing in n, not &n
print n
and now n will be 3. I think C++ and PHP can let you do that, using
their reference (alias) mechanism. And C, Python, and Ruby probably
won't le
On Sep 17, 11:04 pm, Lloyd Linklater <[EMAIL PROTECTED]> wrote:
> SpringFlowers AutumnMoon wrote:
> > Is that the case: if a is an object, then b = a is only copying the
> > reference?
>
> That and it adds a counter.
>
> a = ["foo", "bar"]
> b = a
> b[0] = "bite me"
> p a, b
>
> a = "different"
> p
The meaning of a = b in object oriented languages.
I just want to confirm that in OOP, if a is an object, then b = a is
only copying the reference.
(to make it to the most basic form:
a is 4 bytes, let's say, at memory location 0x1000
On Sep 16, 6:56 pm, Steve Holden <[EMAIL PROTECTED]> wrote:
> Summercool wrote:
> > how come a program that runs directly doesn't need to be optimized
> > into bytecode first? Or... is it that the interpreter will just run
> > the program as it goes by, without e
On Sep 16, 10:36 am, Marc 'BlackJack' Rintsch <[EMAIL PROTECTED]> wrote:
>
> The `*.pyc` files are usually only created when you import a module, not
> when a module is run directly.
how come a program that runs directly doesn't need to be optimized
into bytecode first? Or... is it that the inter
so i have always heard of the .pyc files but for some reason i
don't see them on the Windows platform... when i have a program
called try.py and after running it for ages, i still don't have a
try.pyc file in my folder even if i turn the "show hidden file" to on.
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i think in Ruby, if you have an array (or list) of integers
foo = [1, 2, 3]
you can use foo.join(",") to join them into a string "1,2,3"
in Python... is the method to use ",".join() ? but then it must take
a list of strings... not integers...
any fast method?
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