Thanks all for the answers.
Oscar Benjamin wrote:
print(('{}th\n' * len(a)).format(*a))
print(''.join(map('{}th\n'.format, a)))
Those two look closest to what I was hoping for, I guess, but as Chris
Angelico said, it probably is clearer to just loop over the range.
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In BASH, I can have a single format descriptor for a list:
$ a='4 5 6 7'
$ printf "%sth\n" $a
4th
5th
6th
7th
Is this not possible in Python? Using "join" rather than "format" still
doesn't quite do the job:
>>> a = range(4, 8)
>>> print ('th\n'.join(map(str,a)))
4th
5th
6th
7
Is there an eleg
On Fri, 05 Jun 2015 14:55:11 +0200, Todd wrote:
> Numpy arrays are not lists, they are numpy arrays. They are two
> different data types with different behaviors. In lists, slicing is a
> copy. In numpy arrays, it is a view (a data structure representing some
> part of another data structure).
I saw somewhere on the net that you can copy a list with slicing. So
what's happening when I try it with a numpy array?
>>> a = numpy.array([1,2,3])
>>> b = a[:]
>>> a is b
False
>>> b[1] = 9
>>> a
array([1, 9, 3])
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