Hi,
I experience several exceptions from python's logging system when using the
rollover feature on Windows.
Traceback (most recent call last):
File "c:\Python24\lib\logging\handlers.py", line 62, in emit
if self.shouldRollover(record):
File "c:\Python24\lib\logging\handlers.py", line 132
Pierre Barbier de Reuille wrote:
>
> Best answer is : try it :)
> use the "timeit" module (in the standard lib) to do so ...
Ok, (a second time. I hope the first post was cancelled as it was false)
import timeit
s = """\
a,b,c1,c2 = zip(*[(x[2],x[4], x[2]-x[1], x[2] - x[3]) for x in z])
"""
t
Pierre Barbier de Reuille wrote:
> Best answer is : try it :)
> use the "timeit" module (in the standard lib) to do so ...
Ok,
import timeit
s = """\
a,b,c1,c2 = zip(*[(x[2],x[4], x[2]-x[1], x[2] - x[3]) for x in z])
"""
t = timeit.Timer(stmt=s,setup="z = [(1,2,3,4,5)]*1000")
print "%.2f usec/p
Diez B. Roggisch wrote:
> zip(*[(1,4),(2,5),(3,6)])
>
Thanks :) I knew it must be simple. The asterics - thing was new to me.
By the way: What is faster?
this:
z = [(1,4),(2,5),(3,6)
a,b = zip(*[(x[0], x[0]-x[1]) for x in z])
or:
a = []
b = []
for x in z:
a.append(x[0])
b.append(x[0]-x[
Hi,
I can find examples to convert lists into a list of tuples like:
>>> map(None,[1,2,3],[4,5,6])
[(1,4),(2,5),(3,6)]
but how is it done vice versa?
Oliver
--
http://mail.python.org/mailman/listinfo/python-list
Hi
what will be the fastest solution to following problem
class a:
def __init__(self):
self.varA = 0
self.varB = 0
s.o. ...
listA = [a]*10
varA = []
varB = []
for l in listA:
varA.append(l.varA)
varB.append(l.varB)
s.o. ...
I could think of:
[varA.append(l.varA) fo
