Re: parsing RSS XML feed for item value

2013-11-20 Thread Larry Wilson
Thank you folks, now I know what I don't know and have a solution. -- https://mail.python.org/mailman/listinfo/python-list

Re: parsing RSS XML feed for item value

2013-11-20 Thread Larry Wilson
>>> feed.entries[0].w_current {'temperature': u'20.3', 'dewpoint': u'18.6', 'windgusts': u'29.6', 'rain': u'0.6', 'humidity': u'90', 'pressure': u'0.0', 'windspeed': u'22.2', 'winddirection': u'SSW'} >>> in the above I get the subitem as shown. How do I extract the label, values pairs? -- http

parsing RSS XML feed for item value

2013-11-19 Thread Larry Wilson
Wanting to parse out the the temperature value in the "http://rss.weather.com.au/nsw/newcastle"; === http://rss.weather.com.au/w.dtd";> Weather.com.au - Newcastle Weather http://www.weather.com.au/nsw/newcast