Thank you for your reply.
> Perhaps you are using grep, or you have stumbled on the old deprecated
> "regex" module and are using that instead of the "re" module. Perhaps
> not as you are using only 2 plain vanilla RE operations which should
> work the same way everywhere. Perhaps you are having t
Oh yea, I see what's my confusion now. In the first string, I didn't
consider 11 and 0 matches the pattern without the repetition. Actually
what I did is I entered the pattern and the test strings into kudos (a
python regexp debugger) and got the match groups, which didn't have 11
and 0 as matche
; or ``010"
> or ``11",
> right?:)
Why it must expect "010"? Why not say "0110", since 1* can represent 0
or more repetitions.
>
>
> Kevin CH 寫道：
>
> > Hi,
> >
> > I'm currently running into a confusion on regex and hop
Hi,
I'm currently running into a confusion on regex and hopefully you guys
can clear it up for me.
Suppose I have a regular expression (0|(1(01*0)*1))* and two test
strings: 110_1011101_ and _101101_1. (The underscores are not part of
the string. They are added to show that both string has a sub
