Sorry, i should say I'm using pythonxy, maybe it imports other things.
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Peter Otten於 2014年12月12日星期五UTC+8下午8時32分55秒寫道：
> Jussi Piitulainen wrote:
>
> > KK Sasa writes:
> >
> >> def p(x,t,point,z,obs):
> >> d = x[0]
> >> tau = [0]+[x[1:point]]
> >> a = x[point:len(x)]
> >> at = sum(i*j
Jussi Piitulainen於 2014年12月12日星期五UTC+8下午7時12分39秒寫道：
> KK Sasa writes:
>
> > def p(x,t,point,z,obs):
> > d = x[0]
> > tau = [0]+[x[1:point]]
> > a = x[point:len(x)]
> > at = sum(i*j for i, j in zip(a, t))
> > nu = [exp(z[k]
Peter Otten於 2014年12月12日星期五UTC+8下午5時13分58秒寫道：
> KK Sasa wrote:
>
> > Mark Lawrence於 2014年12月12日星期五UTC+8下午3時17分43秒寫道：
> >> On 12/12/2014 06:22, KK Sasa wrote:
> >> > Hi there,
> >> >
> >> > The list comprehension is results = [d2(t[
Mark Lawrence於 2014年12月12日星期五UTC+8下午3時17分43秒寫道：
> On 12/12/2014 06:22, KK Sasa wrote:
> > Hi there,
> >
> > The list comprehension is results = [d2(t[k]) for k in xrange(1000)], where
> > d2 is a function returning a list, say [x1,x2,x3,x4] for one example. So
> &g
Hi there,
The list comprehension is results = [d2(t[k]) for k in xrange(1000)], where d2
is a function returning a list, say [x1,x2,x3,x4] for one example. So "results"
is a list consisting of 1000 lists, each of length four. Here, what I want to
get is the sum of 1000 lists, and then the resul
