Another option would be to refactor your function so that it is a generator
expression using the yield keyword.
On Sun, Jun 17, 2012 at 7:40 PM, Peter Otten <__pete...@web.de> wrote:
> Gelonida N wrote:
>
> > I'm having a module, which should lazily evaluate one of it's variables.
> > Meaning th
string.split(',') will give you an array.
Example:
'AAA,",,",EEE,FFF,GGG '.split(',')
['AAA', '"', '', '"', 'EEE', 'FFF', 'GGG']
On Wed, Jun 13, 2012 at 10:53 PM, Chris Rebert wrote:
> n Wed, Jun 13, 2012 at 7:29 PM, bruce g wrote:
> > What is the best way to parse a
Seems like what you need is
from othermodule import bb
def aa():
bb()
On Tue, Jun 12, 2012 at 2:51 PM, Ethan Furman wrote:
> Julio Sergio wrote:
>
>> Jose H. Martinez gmail.com> writes:
>>
>>
>>> You should define the function first and then c
You should define the function first and then call it.
def something(i):
return i
a = something(5)
If you want a reference to the function somewhere else you can do this:
global alias = something
print alias(i)
On Tue, Jun 12, 2012 at 1:53 PM, Julio Sergio wrote:
> I'm puzzled with
