Hi,
I have a string like this:
invalidStr = "192.168.*.1"
I want to be sure I don't get a * followed by a number, i.e. I want
invalidStr to be invalid. So I do:
numberAfterStar = re.compile(r'\*.*\d')
Now, here's the fun:
If I run:
if numberAfterStar.findall(invalidStr):
print "Found it wi
Rocco:
thanks for your response. The examples were just made up. I don't
normally use 'dict' and 'str'.
I know I can create a dictionary with the variables I want, etc. My
question is not how to solve the problem, or how to come up with a
work-around (I'm getting pretty good at this one :), so my q
Hi,
I have a dictionary, a string, and I'm creating another string, like
this:
dict = {}
dict[beatles] = "need"
str = "love"
mystr = """All you %(dict[beatles])s is %(str)s""" % locals()
Why do I get
keyerror: 'dict[one]'?
Is there a way to reference the elements in a dictionary with locals()
o
Hi,
I have a dictionary for counting ocurrences of strings in a document.
The dictionary looks like this:
'hello':135
'goodbye':30
'lucy':4
'sky':55
'diamonds':239843
'yesterday':4
I want to print the dictionary so I see most common words first:
'diamonds':239843
'hello':135
'sky':55
'goodbye':3