posed that most discussant want to see the reply message
instantly when they open the mail. They already know what is going on
and no need to pass through all those previous message. "top posting"
seems more reasonable to me:-)
--Jach
mm0fmf at 2018/10/2 AM 05:05 wrote:
On 01/10/2018 10:1
ep 2018 17:45:52 -0700, Rick Johnson wrote:
Jach Fong wrote:
I get a string item, for example path[0], from path =
os.get_exec_path()
It's something like "\\Borland\\Bcc55\\Include", a Python string.
I want to use this "string" in a subprocess command as a parameter.
Obviou
Yes, you are right, it's just the way Python display the '\'.
Thank you.
Gregory Ewing at 2018/9/28 PM 02:02 wrote:
Jach Fong wrote:
I get a string item, for example path[0], from path = os.get_exec_path()
It's something like "\\Borland\\Bcc55\\Include"
I
I get a string item, for example path[0], from path = os.get_exec_path()
It's something like "\\Borland\\Bcc55\\Include", a Python string.
I want to use this "string" in a subprocess command as a parameter.
Obviously this command can only recognize "\Borland\Bcc55\Include".
I know there must have
nt
Deleted breakpoint 1 at c:\test\buginpdb.py:3
> c:\test\buginpdb.py(3)()
-> print('bad password')
(Pdb) cont
bad password
The program exited via sys.exit(). Exit status: None
> c:\test\buginpdb.py(1)()
-> password = 'bad'
(Pdb) q
C:\test>
O
y.py", line 85, in _run_code
exec(code, run_globals)
File "C:\Python34\lib\pdb.py", line 1688, in
pdb.main()
File "C:\Python34\lib\pdb.py", line 1680, in main
pdb.interaction(None, t)
File "C:\Python34\lib\pdb.py", line 346, in interaction
self._cmdloop()
File "C:\Python34\lib\pdb.py", line 319, in _cmdloop
self.cmdloop()
File "C:\Python34\lib\cmd.py", line 126, in cmdloop
line = input(self.prompt)
ValueError: I/O operation on closed file.
D:\Works\Python>
How to get rid of these?
Best Regards,
Jach Fong
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Terry Reedy at 2018/6/19 PM 08:35 wrote:
On 6/18/2018 8:38 PM, sa...@caprilion.com.tw wrote:
Grant Edwards at 2018/6/18 PM 10:36 wrote:
On 2018-06-17, Jach Fong wrote:
The "address" of the Font object 'TkDefaultFont' changes, why?
What makes you think it's the sa
Jim Lee at 2018/6/19 PM 03:44 wrote:
On 06/18/2018 09:22 PM, Jach Fong wrote:
Ben Finney at 2018/6/19 PM 10:20 wrote:
Jach Fong writes:
Although it passed the first examination, I have no idea if it can
work correctly in the real application:-)
Neither do I. What is the real-world
Ben Finney at 2018/6/19 PM 10:20 wrote:
Jach Fong writes:
Although it passed the first examination, I have no idea if it can
work correctly in the real application:-)
Neither do I. What is the real-world problem you are trying to solve?
Why do you think this (and not some more idiomatic
Ben Finney at 2018/6/18 PM 03:29 wrote:
Jach Fong writes:
I also make a test of my own and it fails too.
class A:
... objs = []
... def __init__(self, exists=False):
... if exists: self = self.objs[0]
The function parameters (bound here to the names ‘self’, ‘exists
the correct value. As others said, this is all
handled in a __new__ method. But none of this has much to do with
tkinter instances.
On 6/18/2018 5:09 AM, Terry Reedy wrote:
On 6/18/2018 12:48 AM, Jach Fong wrote:
After looking into the \tkiniter\font.py source file, triggered by Jim's
hi
lass A:
... objs = []
... def __init__(self, exists=False):
... if exists: self = self.objs[0]
... else: self.objs.append(self)
...
>>> a0 = A()
>>> id(a0)
35569968
>>> a1 = A(exists=True)
>>> id(a1)
35572336
What I expect is that id(a0) and
Steven D'Aprano at 2018/6/17 PM 04:19 wrote:
On Sun, 17 Jun 2018 15:08:27 +0800, Jach Fong wrote:
The "address" of the Font object 'TkDefaultFont' changes, why?
Its not an address, it is an ID number.
The ID number changes because you get a different object each t
t;>> tk.Label(root, text='label one', font='TkDefaultFont').pack()
>>> from tkinter import font
>>> font.nametofont('TkDefaultFont')
>>> font.nametofont('TkDefaultFont')
>>>
The "address" of the Font ob
Alister via Python-list at 2018/6/13 PM 08:43 wrote:
IMHO, there is no reason to check the *args has to appear at last in
positional argument list in a function call because of there is no
"unknown number of parameters" at the time of unpacking. It should be
alright to write line 19
action(
ly unrelated. The "*any" notation used in different places
with different meaning, such as defining arbitrary argument, unpacking
argument or even in an assignment(a,*b=any). Maybe it will be better to
stop this syntax checking and lets both statements below valid:-)
acti
On Sun, 03 Jun 2018 10:55:04 +0800, Jach Fong wrote:
The attached is a script which can run under Python 3.4/Windows Vista
correctly. One thing make me puzzled is that the "any + context" at
line 18. The "any" was passed as an integer from line 43 and the
"context" was
jf...@ms4.hinet.net wrote:
The attached is a script which can run under Python 3.4/Windows Vista
correctly. One thing make me puzzled is that the "any + context" at line
18. The "any" was passed as an integer from line 43 and the "context"
was defined as a tuple at li
# 3.x need list for map, range ok
lambda event: list(map(onEvent, range(2))) )
root.mainloop()
Ben Finney 於 2018/6/3 上午 11:57 寫道:
Jach Fong writes:
The attached is a script
Thanks for making an example script. Instead of attaching it, please
post it along with your me
run under Python 3.4/Windows Vista
correctly. One thing make me puzzled is that the "any + context" at line
18. The "any" was passed as an integer from line 43 and the "context"
was defined as a tuple at line 35. This concatenation works! how?
Best Regards,
Jach Fong
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tion works! how?
Best Regards,
Jach Fong
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import _thread as thread
import queue
threadQueue = queue.Queue(maxsize=0)
def queueChecker(wi
Abdur-Rahmaan Janhangeer at 2018/5/17 PM 04:23 wrote:
if then a more convenient way might be found to naturally remove and return
the list
maybe it was not included as one might want to remove the list only
x = [1]
x.remove(1)
as opposed to
x = [1]
x.remove(1)
new_list = x
IMO, this way is
Gregory Ewing at 2018/4/15 PM 08:20 wrote:
Jach Fong wrote:
>>> pvoid = ctypes.c_void_p(ctypes.addressof(buf0))
>>> pvoid.contents
Traceback (most recent call last):
File "", line 1, in
AttributeError: 'c_void_p' object has no attribute 'conten
eryk sun at 2018/4/14 PM 05:27 wrote:
On Fri, Apr 13, 2018 at 8:44 AM, Jach Fong wrote:
After studying the example you explained in your previous post replied to
Gregory Ewing, I had noticed that until today I was totally misunderstand
the meaning of the c_char_p. I always think it "
eryk sun at 2018/4/13 PM 12:16 wrote:
On Fri, Apr 13, 2018 at 12:38 AM, Jach Fong wrote:
Gregory Ewing at 2018/4/13 上午 07:25 wrote:
To get around this, you may need to declare the return type
as POINTER(c_char) instead:
For a general character pointer that may also point to binary data
Gregory Ewing at 2018/4/13 上午 07:25 wrote:
On Thu, Apr 12, 2018 at 2:16 PM, wrote:
This C function returns a buffer which I declared it as a
ctypes.c_char_p. The buffer has size 0x1 bytes long and the valid
data may vary from a few bytes to the whole size.
I think we need to see the co
This is the first time I am using python-list to interact with
comp.lang.python forum (because there are so many spam when using
browser to view it) so forgive me if something goes wrong.
Python already treat the returned buffer as 'bytes'. The problem is
Python don't know its size (or decides
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