Steve,
> I am looking for the python2.7 function(s) to parse a string from a colon
> character ":"
>
> Sounds simple enough.
>
> For example, a string like "123456:789". I just need the "123456"
> substring.(left of the :)
How about:
newstr = str[:str.find(':')]
--
GC
smime.p7s
Descriptio
Ron,
LOGFILE, maxBytes=(1048576*10), backupCount=5
What am I doing wrong here, I don't get it.
10 * 1048576 = 10MB
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GC
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script is doing, or to be shown the Python way of how to accomplish
something like that. Surprisingly, there's no mention of regular
expressions in the Perl Phrasebook at
http://wiki.python.org/moin/PerlPhrasebook.
-- Gary Chambers
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@{$cnames{$host}});
print " ";
}
print "$ip{$host}\n";
}
exit 0;
Will someone please provide some insight on how to accomplish that task in
Python? I am unable to continually (i.e. it stops after displaying a single
line) loop through the output while testing for the matches on the two
regular expressions. Thank you.
-- Gary Chambers
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