On Jun 15, 2:37 pm, Peter Otten <__pete...@web.de> wrote:
> >>> from itertools import cycle, izip
> >>> sum(sign*i*i for sign, i in izip(cycle([1]*3+[-1]*2), range(1, 2011)))
Wow!! :D
I didn't knew cycle, great! With that i can reduce my solution (which
isn't still elegant as your) to:
print redu
On Jun 15, 1:49 pm, superpollo wrote:
> goal (from e.c.m.): evaluate
> 1^2+2^2+3^2-4^2-5^2+6^2+7^2+8^2-9^2-10^2+...-2010^2, where each three
> consecutive + must be followed by two - (^ meaning ** in this context)
My functional approach :)
from operator import add
from functools import reduce
