On Mon, Jan 3, 2022 at 8:06 AM Joao Marques wrote:
> Good morning: I have a very simple question: I want to start writing
> programs in Python so I went to the Microsoft Store and installed
> Python3.9. No problem so far. I would prefer to have a gui interface, an
> interface that I can use file-
On 2022-01-05 at 08:30:30 +1100,
Cameron Simpson wrote:
> On 04Jan2022 21:03, Marco Sulla wrote:
> >On Tue, 4 Jan 2022 at 19:38, Chris Angelico wrote:
> >> [...] should the keys view be considered
> >> frozen or not? Remember the set of keys can change (when the
> >> underlying dict changes).
>
On 2022-01-04 22:57, Israel Brewster wrote:
I’m running into an issue with shapely that is baffling me. Perhaps someone
here can help out?
When running shapely directly from a python 3.8 interpreter, it works as
expected:
import shapely
shapely.__version__
'1.8.0'
from shapely.geometry imp
On Wed, Jan 5, 2022 at 7:04 AM Marco Sulla wrote:
>
> On Tue, 4 Jan 2022 at 19:38, Chris Angelico wrote:
> > [...] should the keys view be considered
> > frozen or not? Remember the set of keys can change (when the
> > underlying dict changes).
>
> Well, also the items can change, but they are re
On 04Jan2022 21:03, Marco Sulla wrote:
>On Tue, 4 Jan 2022 at 19:38, Chris Angelico wrote:
>> [...] should the keys view be considered
>> frozen or not? Remember the set of keys can change (when the
>> underlying dict changes).
>
>Well, also the items can change, but they are returned as tuples w
I’m running into an issue with shapely that is baffling me. Perhaps someone
here can help out?
When running shapely directly from a python 3.8 interpreter, it works as
expected:
>>> import shapely
>>> shapely.__version__
'1.8.0'
>>> from shapely.geometry import Polygon
>>> bounds = [-164.296358
On Tue, 4 Jan 2022 at 19:38, Chris Angelico wrote:
> [...] should the keys view be considered
> frozen or not? Remember the set of keys can change (when the
> underlying dict changes).
Well, also the items can change, but they are returned as tuples with
2 elements.
It seems to me that the stdli
On Wed, Jan 5, 2022 at 5:29 AM Marco Sulla wrote:
>
> $ python
> Python 3.10.0 (heads/3.10-dirty:f6e8b80d20, Nov 18 2021, 19:16:18)
> [GCC 10.1.1 20200718] on linux
> Type "help", "copyright", "credits" or "license" for more information.
> >>> a = {1:2}
> >>> c = {1:2, 3:4}
> >>> c.keys() - a.keys
$ python
Python 3.10.0 (heads/3.10-dirty:f6e8b80d20, Nov 18 2021, 19:16:18)
[GCC 10.1.1 20200718] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> a = {1:2}
>>> c = {1:2, 3:4}
>>> c.keys() - a.keys()
{3}
>>>
Why not frozenset({3})?
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