Eko palypse wrote:
> exec('import test01', globals())
> print('f3 out', x)
>
> # result exception, expected but because f1 didn't throw an exception
> # I'm confused. module test01 has only this two lines
> x += 1
> print('f3 in:', x)
The lines above run in the test01's global namespace, not in
Manfred Lotz wrote:
>> Not related to your question, but:
>> You seem to try to convert a Windows wildcard pattern to a regex
>> pattern.
>
> No, I'm on Linux.
>
> Shortly, after I had posted the question I discovered fnmatch() in the
> standard library, and I changed my code accordingly.
I wou
Eko palypse writes:
> Why does f1 work? I've expected an exception as no global dict has been
> provided
> ...
>def f1(...):
> exec("...")
>...
The documentation ("https://docs.python.org/3/library/functions.html#exec";)
tells you:
exec(object[, globals[, locals]])
...
In all cases, if the opt
On Wed, 18 Sep 2019 22:01:34 +0200
"Ralf M." wrote:
> Am 17.09.2019 um 20:59 schrieb Manfred Lotz:
> > I have a function like follows
> >
> > def regex_from_filepat(fpat):
> > rfpat = fpat.replace('.', '\\.') \
> >.replace('%', '.') \
> >.rep
On Wednesday, September 18, 2019 at 9:01:21 AM UTC-4, Manfred Lotz wrote:
> On Wed, 18 Sep 2019 08:30:08 +0200
> Peter Otten <__pete...@web.de> wrote:
>
> > Manfred Lotz wrote:
> >
> > > I have a function like follows
> > >
> > > def regex_from_filepat(fpat):
> > > rfpat = fpat.replace('.',
Why does f1 work? I've expected an exception as no global dict has been
provided, and why does throw f3 an exception if it does, more or less, the same
as f1?
x += 5
def f1():
exec("x += 1; print('f1 in:', x)")
return x
print('f1 out', f1())
# result => f1 in: 6
# result => f1 out 5
x
On 2019-09-18 4:01 p.m., Ralf M. wrote:
> Am 17.09.2019 um 20:59 schrieb Manfred Lotz:
>> I have a function like follows
>>
>> def regex_from_filepat(fpat):
>> rfpat = fpat.replace('.', '\\.') \
>> .replace('%', '.') \
>> .replace('*', '.*')
>>
>
On Thu, Sep 19, 2019 at 6:20 AM Ralf M. wrote:
>
> Am 17.09.2019 um 20:59 schrieb Manfred Lotz:
> > I have a function like follows
> >
> > def regex_from_filepat(fpat):
> > rfpat = fpat.replace('.', '\\.') \
> >.replace('%', '.') \
> >.replace(
Am 17.09.2019 um 20:59 schrieb Manfred Lotz:
I have a function like follows
def regex_from_filepat(fpat):
rfpat = fpat.replace('.', '\\.') \
.replace('%', '.') \
.replace('*', '.*')
return '^' + rfpat + '$'
As I don't want to have the r
On Wed, 18 Sep 2019 08:30:08 +0200
Peter Otten <__pete...@web.de> wrote:
> Manfred Lotz wrote:
>
> > I have a function like follows
> >
> > def regex_from_filepat(fpat):
> > rfpat = fpat.replace('.', '\\.') \
> > .replace('%', '.') \
> > .replace(
On Wed, 18 Sep 2019 09:52:21 +0200
Wolfgang Maier wrote:
> On 17.09.19 20:59, Manfred Lotz wrote:
> > I have a function like follows
> >
> > def regex_from_filepat(fpat):
> > rfpat = fpat.replace('.', '\\.') \
> > .replace('%', '.') \
> > .replace
On 18Sep2019 03:36, eryk sun wrote:
On 9/17/19, Cameron Simpson wrote:
If you just want this for your running program's internals this may not
matter, but if you're recording the result somewhere then abspath might
get you a more "stable" path in the above scenario.
If a path has ".." compo
Cameron Simpson writes:
> On 17Sep2019 15:09, Hongyi Zhao wrote:
>>See the following two methods for obtaining the file's path:
>>
>>os.path.realpath(file)
>>or
>>os.path.abspath(os.path.expanduser(file))
>>
>>Which is more robust?
>
> My inclination is often to use abspath, because it may bette
On 9/17/19, Cameron Simpson wrote:
>
> If you just want this for your running program's internals this may not
> matter, but if you're recording the result somewhere then abspath might
> get you a more "stable" path in the above scenario.
If a path has ".." components, the abspath() result may be
On 17.09.19 20:59, Manfred Lotz wrote:
> I have a function like follows
>
> def regex_from_filepat(fpat):
> rfpat = fpat.replace('.', '\\.') \
> .replace('%', '.') \
> .replace('*', '.*')
>
> return '^' + rfpat + '$'
>
>
> As I don't want to
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