for i in range(len(A.hp)):
for j in range(len(run_parameters.bits_Mod)):
req_slots[j] = math.ceil((A.T[i])
for g in Temp[i]["Available_ranges"][j]:
for s in range(g[0], g[-1]):
if (s+req_slots[j]-1) <= g[-1]:
if (Temp[i]['cost'][
On 02/07/2019 09:00 PM, Steve wrote:
> BeeWare looks as if it requires Java, does it?
> Is it exclusively java?
Kind of. You do your coding in Python, then that's compiled to python
byte code, which is then translated to Java byte code. You'll need the
Android SDK, even if you're not using Java
BeeWare looks as if it requires Java, does it?
Is it exclusively java?
=
Footnote:
Zamboni locks up after running into large patch of loose teeth.
-Original Message-
From: Python-list On
Behalf Of Mario R. Osorio
Sent: Tuesday, February 5, 2019 8:58 AM
To: python-list@py
Grant Edwards writes:
> On 2019-02-07, Ben Bacarisse wrote:
>> Ian Clark writes:
>>
>>> This is my whack at it, I can't wait to hear about it being the wrong big o
>>> notation!
>>>
>>> numbers=[]
>>>
>>> while len(numbers) < 10:
>>> try:
>>> chip = int(input('please enter an intege
Bart writes:
> On 07/02/2019 20:45, Ben Bacarisse wrote:
>> Ian Clark writes:
>>
>>> This is my whack at it, I can't wait to hear about it being the wrong big o
>>> notation!
>>>
>>> numbers=[]
>>>
>>> while len(numbers) < 10:
>>> try:
>>> chip = int(input('please enter an integer:
On 2/4/19 3:20 PM, Steve wrote:
I have written my first python program (600 lines!) to help control my blood
sugar and it has been so successful that my A1c dropped form 9.3 to an
impressive 6.4. It will be much more useful if I had it on my phone.
(MotoG, Android) The .py file reads/writes t
On 2019-02-07, Ben Bacarisse wrote:
> Ian Clark writes:
>
>> This is my whack at it, I can't wait to hear about it being the wrong big o
>> notation!
>>
>> numbers=[]
>>
>> while len(numbers) < 10:
>> try:
>> chip = int(input('please enter an integer: '))
>> except ValueError:
>>
Ian Clark writes:
> This is my whack at it, I can't wait to hear about it being the wrong big o
> notation!
>
> numbers=[]
>
> while len(numbers) < 10:
> try:
> chip = int(input('please enter an integer: '))
> except ValueError:
> print('that is not a number, try again')
>
I just realized that input has changed in Python 3 and I was using Python
2.7.13 with from __future__ import print_function and some others, but not that.
In Python 3 the int( ) or float( ) cast is necessary because input( ) does what
raw_input( ) did in Python 2; raw_input( ) name is therefore r
This is my whack at it, I can't wait to hear about it being the wrong big o
notation!
numbers=[]
while len(numbers) < 10:
try:
chip = int(input('please enter an integer: '))
except ValueError:
print('that is not a number, try again')
else:
numbers.append(chip)
Well of course that doesn't work. For starters, x is an int or a float value.
After the loop It holds the 10th value. It might hold 432.7 ... It is not a
list.
The default start for range is 0. The stop value, as you already know, is not
part of the range. So I will use range(10).
In the
I'd say if the documentation mentions it, but doesn't say why, then we're not
gonna be able to do much better for you as far as "why" goes.
http://pytz.sourceforge.net/
"Unfortunately using the tzinfo argument of the standard datetime constructors
"does not work" with pytz for many timezones."
Am 05.02.19 um 02:20 schrieb DL Neil:
So, even with the French making their dates into sentences, not a single
one uses ordinals!
- did the computer people in all these languages/cultures decide that
the more numeric approach was better/easier/...
(ie simpler/less-complex)
:)
For the two lan
I made a small script to practise with timezones:
#!/usr/bin/env python3
# -*- coding: utf_8 -*-
from datetime import datetime, timedelta
from pytz import timezone
import pytz
amsterdam_datetime = datetime(2018, 12, 17, 11, 31, 26,
tzinfo=timezone('Europe/Amsterdam'))
print(amsterdam_datetime)
utc
On Thu, Feb 7, 2019 at 6:31 AM ^Bart wrote:
>
> I thought something like it but doesn't work...
>
> for n in range(1, 11):
> x = input("Insert a number: ")
The above, keeps replacing x with each input value. You don't want
that. Think about appending the input value to a list
>
> for y in
I thought something like it but doesn't work...
for n in range(1, 11):
x = input("Insert a number: ")
for y in range(x):
sum = y
print ("The sum is: ",y)
--
https://mail.python.org/mailman/listinfo/python-list
Further to our discussion of how to improve a code review's discovery of
the mistaken handling of a for...else... construct:-
Yesterday was a national holiday, but today gave some opportunity to
research. Way back in 2009 there was spirited discussion over on the
Python Ideas list (warning, e
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