On Fri, Sep 9, 2016 at 9:36 AM, Xavier Combelle
wrote:
> and eventually this one work in all case of iterable
>
> def shuffled3(iterable):
> result = list(iterable)
> random.shuffle(result)
> return result
>
This is the one obvious way to do this. Not all iterables can
logically be sh
When thinking about the shuffled thread, it occurred to me that it was
quite easy to pass an iterable and expect the iterable to be shuffled.
but two mentioned implementation are close to success but fail by not
taking this use case in account:
def shuffled1(iterable):
result = iterable[:]
