26.05.14 10:59, raymond.hettinger написав(ла):
+result = [(elem, i) for i, elem in zip(range(n), it)]
Perhaps it is worth to add simple comment explaining why this is not
equivalent to just list(zip(it, range(n))). Otherwise it can be
unintentionally "optimized" in future.
On Tue, May 27, 2014 at 6:58 PM, Serhiy Storchaka wrote:
> 26.05.14 10:59, raymond.hettinger написав(ла):
>>
>> +result = [(elem, i) for i, elem in zip(range(n), it)]
>
>
> Perhaps it is worth to add simple comment explaining why this is not
> equivalent to just list(zip(it, range(n))). Ot
On Tue, May 27, 2014 at 4:05 AM, Chris Angelico wrote:
> On Tue, May 27, 2014 at 6:58 PM, Serhiy Storchaka wrote:
>> 26.05.14 10:59, raymond.hettinger написав(ла):
>>>
>>> +result = [(elem, i) for i, elem in zip(range(n), it)]
>>
>>
>> Perhaps it is worth to add simple comment explaining
On Tue, May 27, 2014 at 2:45 PM, Michael Urman wrote:
> On Tue, May 27, 2014 at 4:05 AM, Chris Angelico wrote:
>> On Tue, May 27, 2014 at 6:58 PM, Serhiy Storchaka
>> wrote:
>>> 26.05.14 10:59, raymond.hettinger написав(ла):
+result = [(elem, i) for i, elem in zip(range(n), it
On 27.05.2014 11:05, Chris Angelico wrote:
> On Tue, May 27, 2014 at 6:58 PM, Serhiy Storchaka wrote:
>> 26.05.14 10:59, raymond.hettinger написав(ла):
>>>
>>> +result = [(elem, i) for i, elem in zip(range(n), it)]
>>
>>
>> Perhaps it is worth to add simple comment explaining why this is n
On May 27, 2014, at 1:58 AM, Serhiy Storchaka wrote:
> Perhaps it is worth to add simple comment explaining why this is not
> equivalent to just list(zip(it, range(n))). Otherwise it can be
> unintentionally "optimized" in future.
FWIW, that is covered by the test cases.
If you substitute lis
On 27/05/2014 13:44, Tal Einat wrote:
On Tue, May 27, 2014 at 2:45 PM, Michael Urman wrote:
On Tue, May 27, 2014 at 4:05 AM, Chris Angelico wrote:
On Tue, May 27, 2014 at 6:58 PM, Serhiy Storchaka wrote:
26.05.14 10:59, raymond.hettinger написав(ла):
+result = [(elem, i) for i, el
