New submission from X. Yan :
I am familiar with quite a few languages such as C++, C, PASCAL, Matlab, etc.,
but starting to practice Python. When I tested the code:
def f(a, L=[]):
L.append(a)
return L
followed by calls as follows,
v1 = f(1)
v2 = f(2)
, to my surprise, I
X. Yan added the comment:
Hi Serhiy,
Thanks for your reply. However, the issue I reported was not about sharing the
default value. I understand that the parameter L would keep its value [1] from
function f's first run, and used it in the second run to get [1, 2].
My point is tha
X. Yan added the comment:
I see.
Thanks for the detailed explanations.
Best,
Xiaogang
On 6/11/2018 2:00 PM, Steven D'Aprano wrote:
> Steven D'Aprano added the comment:
>
> Both names "v1" and "v2" refer to the same object. Python does not make
>
