New submission from Pocas :
If http:@localhost url is entered as an argument value of the urlpasre()
function, the parser cannot parse it properly. Since http:@localhost is a valid
URL, the character after the @ character must be parsed as a hostname.
Python 3.9.10 (main, Jan 15 2022, 11:48
Change by Pocas :
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type: performance -> security
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Python tracker
<https://bugs.python.org/issue46870>
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Pocas added the comment:
>>> print(urlparse('https:\\google.com'))
ParseResult(scheme='https', netloc='', path='\\google.com', params='',
query='', fragment='')
>>> print(urlparse('https://googl
Pocas added the comment:
Nice Check. So what do you think about this issue? I want to hear your opinions.
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Python tracker
<https://bugs.python.org/issue46
