[issue21979] SyntaxError not raised on "0xaor 1"

2014-07-14 Thread Mika Eloranta
New submission from Mika Eloranta: The following are expected to raise SyntaxError, but they don't: >>> 0xfor python is weird in ways 15 >>> [0xaor 1, 0xbor 1, 0xcor 1, 0xdor 1, 0xeor 1, 0xfor 1] [10, 11, 12, 13, 14, 15] Verified on v2.7.1 and v3.3.2. Probab

[issue21979] SyntaxError not raised on "0xaor 1"

2014-07-14 Thread Mika Eloranta
Mika Eloranta added the comment: Mark, can you explain why the first example is valid syntax, but the second one is not: >>> 0xaor 1 10 >>> 0xaand 1 File "", line 1 0xaand 1 ^ SyntaxError: invalid syntax I do understand how "0xaor 1"

[issue21979] SyntaxError not raised on "0xaor 1"

2014-07-14 Thread Mika Eloranta
Mika Eloranta added the comment: OK, I see... "0xfand 1" is ambiguous "(0xfa)nd 1" vs. "(0xf)and 1". So, while a bit weird, the behavior is consistent: >>> 123not in [], 0xfnot in [], 0xfor 1, 0xafor