Ezio Melotti added the comment:
What Jon said is correct, .group() is equivalent to .group(0) and returns the
whole match. re.findall returns all the groups captured by each set of () as a
list of strings (if there is 0 or 1 group) or a list of tuples (if there are
more than 1).
--
n
Jon Clements added the comment:
Seems consistent to me:
.match, .search and .finditer return a MatchObject whose .group() return the
*entire matched string*. If you use .group(1) you'll get similar results to
.findall() which returns a list of (possibly of tuples) of the captured
groupings.
New submission from Jean-Michel Fauth :
>>> sys.version
2.6.5 (r265:79096, Mar 19 2010, 21:48:26) [MSC v.1500 32 bit
(Intel)]
>>> import re
>>> re.match("[-+]?[0-9]+[.]?[0-9]*([eE][-+]?[0-9]+)?", "1.23e-4").group()
1.23e-4
>>> re.search("[-+]?[0-9]+[.]?[0-9]*([eE][-+]?[0-9]+)?", "1.23e-4").group(
