Eric V. Smith added the comment:
problem_ary[:] creates a copy of problem_ary, so it's equal to:
>>> problem_ary[:]
[['a', 'b', 'c'], ['d', 'e', 'f'], ['g', 'h', 'i']]
The [1] element of that is:
>>> problem_ary[:][1]
['d', 'e', 'f']
So this is working as expected.
I suggest you ask on Sta
New submission from Ritvik S :
I had a problem running the following code. When I ran through what I thought
python was supposed to do, I got a different answer than what python did. I
think this is an error. Here is the code:
problem_ary = [['a','b','c'],['d','e','f'],['g','h','i']]
normal
