Amaury Forgeot d'Arc <[EMAIL PROTECTED]> added the comment:
Yes, the default value expression could be evaluated each time the
function is called without the parameter. But it would be another language.
Default values are computed once, and this is a Python feature.
It can be useful, for example
Torsten Rottmann <[EMAIL PROTECTED]> added the comment:
OK. I've read the Python Reference Manual 7.6 "Function Definition".
It "explains" why this happens.
BUT: Why can`t the compiler make a copy of the default object, if
it's mutable (e.g. a list)? This can't be that difficult.
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Ulrich Eckhardt <[EMAIL PROTECTED]> added the comment:
http://effbot.org/pyfaq/why-are-default-values-shared-between-objects.htm
The same recently cropped up on the users mailinglist under the topic
"default value in __init__".
--
nosy: +eckhardt
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New submission from Torsten Rottmann <[EMAIL PROTECTED]>:
The attached file produced the following result:
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trott$ python2.5 p6.py
[]
[1234]
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I expected both times the empty list since the print
statement prints just a defaulted parameter ("e") which
