chafporte <[EMAIL PROTECTED]> added the comment:
but in python 2.5 you may do this:
if type(lInstance) == types.InstanceType:
...
else:
...
and I don't see an easy way to do this with python 2.6
(feel free to propose a solution if y
chafporte <[EMAIL PROTECTED]> added the comment:
but for a user define class we have:
>class AAA:
>... pass
>
>a = AAA()
>type(a)
and you can compare this with types.InstanceType
and it says True
where for the UserList instance the comparison with
types.InstanceType s
chafporte <[EMAIL PROTECTED]> added the comment:
but like that there is no way to detect if the object
is a class or an instance. type() says it's a class in both case !
___
Python tracker <[EMAIL PROTECTED]>
<http://bugs.
New submission from chafporte <[EMAIL PROTECTED]>:
from UserList import UserList
lu = UserList()
type(lu)
python2.6 prints:
python2.5 prints:
--
components: None
messages: 75885
nosy: chafporte
severity: normal
status: open
title: type of UserList instance returns class inst
