Changes by Andrey Wagin :
--
type: -> security
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<http://bugs.python.org/issue24933>
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Andrey Wagin added the comment:
There is the same behavior for python 3.4
>>> sks[1].send(b"asdfasdfsadfasdfsdfsadfsdfasdfsdfasdfsadfa")
42
>>> sks[0].recv(1, socket.MSG_PEEK | socket.MSG_TRUNC)
b'a\x00Nx\x94\x7f\x00\x00sadfasdfsdfsadfsdfasdfsdfasdfsadfa'
Andrey Wagin added the comment:
sendto(4, "asdfasdfsadfasdfsdfsadfsdfasdfsd"..., 42, 0, NULL, 0) = 42
recvfrom(3,
"a\0n\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\5\0\0\0\0\0\0\0\2\0\0\0"..., 1,
MSG_TRUNC, NULL, NULL) = 42
I think the exit code is interpreted incorrectly. In this
New submission from Andrey Wagin:
In [1]: import socket
In [2]: sks = socket.socketpair(socket.AF_UNIX, socket.SOCK_DGRAM)
In [3]: sks[1].send("asdfasdfsadfasdfsdfsadfsdfasdfsdfasdfsadfa")
Out[3]: 42
In [4]: sks[0].recv(1, socket.MSG_PEEK | socket.MSG_TRUNC)
Out[4]:
'a\x00\x
