On Wed, Jul 21, 2010 at 5:44 PM, BrianTheLion wrote:
> I was
> hoping that some of the more experienced Pylons crew would take a few
> minutes and maybe help compile some "best-practices" that will allow
> others get off the ground more quickly.
There aren't really any definitive answers to these
On Jul 21, 7:13 pm, huydo wrote:
> On Jul 22, 2:17 am, Wyatt Baldwin wrote:
>
>
>
>
>
> > On Jul 21, 5:56 am, huydo wrote:
>
> > > Hi,
>
> > > Just trying to do a direct from the __call__ method in my base.py file
> > > and this is the following exception which I am getting.
>
> > > redirect(u
There was a brief discussion about the controllers in April:
http://groups.google.com/group/pylons-discuss/browse_thread/thread/bcdddffc643cca7a/8a976271d6b990b5
I use multiple controllers. My database schema (and form schemas) are
in my models directory. My Controllers generally segregate
func
On Jul 22, 2:17 am, Wyatt Baldwin wrote:
> On Jul 21, 5:56 am, huydo wrote:
>
>
>
> > Hi,
>
> > Just trying to do a direct from the __call__ method in my base.py file
> > and this is the following exception which I am getting.
>
> > redirect(url(controller='redirect', action='index'))
> > Fil
Hi all,
I've been dabbling in Pylons for about a year now, bringing myself up
to speed on an outstanding enabling technology that shows real depth
and breadth. An experienced Python programmer, I am quite impressed.
The software is mature, and implements a lot of great insight into
what it takes t
When using paste, e.g. loadapp, it goes through
setuptools/pkg_resources, which goes through your app's requires.txt.
Any hacks to allow for pip requirements syntax?
(http://pip.openplans.org/requirement-format.html)
Currently if I try the following, for instance:
-f
http://protobuf-socket-rpc
On Wed, Jul 21, 2010 at 1:03 PM, Jens Hoffrichter
wrote:
> Hi,
>
> On 21 July 2010 21:40, Mike Orr wrote:
>> On Wed, Jul 21, 2010 at 12:33 PM, Ian Wilson
>> wrote:
>>> Hello,
>>>
>>> I think you want something like this.
>>>
>>> from paste.fileapp import FileApp
>>>
>>> # in controller
Hi,
On 21 July 2010 21:40, Mike Orr wrote:
> On Wed, Jul 21, 2010 at 12:33 PM, Ian Wilson
> wrote:
>> Hello,
>>
>> I think you want something like this.
>>
>> from paste.fileapp import FileApp
>>
>> # in controller
>> #...in some action, get the path to serve
>> wsgi_ap
On 2010-7-21 21:40, Mike Orr wrote:
On Wed, Jul 21, 2010 at 12:33 PM, Ian Wilson wrote:
Hello,
I think you want something like this.
from paste.fileapp import FileApp
# in controller
#...in some action, get the path to serve
wsgi_app = FileApp(path)
return
On Wed, Jul 21, 2010 at 12:33 PM, Ian Wilson wrote:
> Hello,
>
> I think you want something like this.
>
> from paste.fileapp import FileApp
>
> # in controller
> #...in some action, get the path to serve
> wsgi_app = FileApp(path)
> return wsgi_app(request.environ
Hello,
I think you want something like this.
from paste.fileapp import FileApp
# in controller
#...in some action, get the path to serve
wsgi_app = FileApp(path)
return wsgi_app(request.environ, self.start_response)
A better solution you might want to look into
Hi everyone,
I looked into the documentation, but couldn't find any mentioning of
what I could return from an action.
I know that I can return a string, most likely rendered from a template.
Is it possible to return a file object from an action, so that the
contents of the file will be delivered
On Jul 21, 5:56 am, huydo wrote:
> Hi,
>
> Just trying to do a direct from the __call__ method in my base.py file
> and this is the following exception which I am getting.
>
> redirect(url(controller='redirect', action='index'))
> File 'c:\\apps\\xbits\\ktrack\\python\\lib\\site-packages\\pylons
Hi,
Just trying to do a direct from the __call__ method in my base.py file
and this is the following exception which I am getting.
redirect(url(controller='redirect', action='index'))
File 'c:\\apps\\xbits\\ktrack\\python\\lib\\site-packages\\pylons-1.0-
py2.5.egg\\pylons\\controllers\\util.py'
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