On Dec 12, 2010, at 10:20 PM, Jerry wrote:
> but not /with/ the 'name' argument (which gives the same error as that
> in my previous post) --
>
>
> @view_config(name='site1_view', route_name='site1',
> renderer='templates/site1.pt')
>
>
> Maybe the doc could have made it clearer that view_conf
Yes this works --
@view_config(route_name='site1', renderer='templates/site1.pt')
but not /with/ the 'name' argument (which gives the same error as that
in my previous post) --
@view_config(name='site1_view', route_name='site1',
renderer='templates/site1.pt')
Maybe the doc could have made i
On Monday, December 13, 2010, blaflamme wrote:
> Yes you can, you must defin to which route name it's related:
> @view_config(name='my_view', context=MyModel, permission='read',
> route_name='site1')
>
> http://docs.pylonshq.com/pyramid/dev/api/view.html#pyramid.view.view_config
Thanks.
Then, I
You must not define the view in your route, that should work:
<__init__.py>
config.add_route('site1', '/site1')
config.scan()
@view_config(route_name='site1', renderer='templates/site1.pt')
def site1_view(request):
return {'foo': 'bar'}
Blaise
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Hi,
I'm also puzzled by the view_config()+config.scan() behavior.
This works --
<__init__.py>
config.add_route('site1', '/site1',
view='myproject.views.site1_view',
view_renderer='templates/site1.pt')
while the below combination doesn't --
<__init__.py>
Yes you can, you must defin to which route name it's related:
@view_config(name='my_view', context=MyModel, permission='read',
route_name='site1')
http://docs.pylonshq.com/pyramid/dev/api/view.html#pyramid.view.view_config
Blaise
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