Sweet. I figured this out..
Still a beginner's question. Feel free to delete this thread.
I needed:
return HTTPFound(location = route_url('root', request, _query=params))
On Feb 1, 1:00 pm, svaha wrote:
> I've been working on a simple form submittal in Pyramid. I tried
> Deform and Pyramid_Sim
I've been working on a simple form submittal in Pyramid. I tried
Deform and Pyramid_Simpleform but I am using a lot of jQuery on the
form that I would like to keep.
Right now, I am using.
params = request.params
...
except formencode.Invalid, e:
request.error = e.error_dict
