You would think that a relatively simple conditional statement should
be quite easy to get
working --- but after many retries and reworks, this has got me
stumped. I look forward to being shown why and (even better) what
actually will work.
First, lets give everyone access to the knowledge bas
if ('$picture_filename1' !== "('' or ''")" )
!== means equal and same variable type.
NULL in the datatbase returns null in the variable. Not the string
'NULL' and not empty string (''), but actual null and I'm not sure
what you mean with the <> around NULL.
Do it like this:
if ($picture_f
