hat directory DOES exist, right?
I assume the is_dir() line is 69 and the opendir() is line 70, correct?
-TG
> -Original Message-
> From: Mike [mailto:[EMAIL PROTECTED]
> Sent: Tuesday, November 30, 2004 12:06 AM
> To: 'Pravin-Kumar'; [EMAIL PROTECTED]
> Subject: RE
[mailto:[EMAIL PROTECTED]
> Sent: Tuesday, November 30, 2004 12:58 AM
> To: [EMAIL PROTECTED]
> Subject: RE: [PHP-WIN] problem to open dir
>
>
> Try changing your $dir variable to:
>
> $dir="C:\\Documents and Settings\\pravin\\Desktop\\abcd2";
>
> Failing t
Also.. Any permissions issues? Can PHP or the user that PHP is running
as access that folder?
> -Original Message-
> From: Pravin-Kumar [mailto:[EMAIL PROTECTED]
> Sent: Tuesday, November 30, 2004 1:28 AM
> To: Mike
> Cc: [EMAIL PROTECTED]
> Subject: RE: [PHP-WIN] p
-
> From: Mike [mailto:[EMAIL PROTECTED]
> Sent: Tuesday, November 30, 2004 12:06 AM
> To: 'Pravin-Kumar'; [EMAIL PROTECTED]
> Subject: RE: [PHP-WIN] problem to open dir
>
>
> When you set the $dir variable, try doing so with single
> quotes - the \
> character
11 4616-1394
>
> -Mensagem original-
> De: Luis Moreira [mailto:[EMAIL PROTECTED]
> Enviada em: terça-feira, 30 de novembro de 2004 08:04
> Para: Pravin-Kumar
> Cc: [EMAIL PROTECTED]
> Assunto: Re: [PHP-WIN] problem to open dir
>
> Remove the double quotes.
&
Remove the double quotes.
$dh = opendir('F:/vyapar-2/test/cdaci');
Pravin-Kumar wrote:
hi list!
$dest='F:/vyapar-2/test/cdaci'; or
$dest='F:\vyapar-2\test\cdaci'; or
$dest='F:\\vyapar-2\\test\\cdaci'; or
$dh = opendir($dest);
$a=dir($dest);
the above code giving following problem on apache 1.3 o
hi list!
$dest='F:/vyapar-2/test/cdaci'; or
$dest='F:\vyapar-2\test\cdaci'; or
$dest='F:\\vyapar-2\\test\\cdaci'; or
$dh = opendir($dest);
$a=dir($dest);
the above code giving following problem on apache 1.3 on windows
Warning: opendir(F:/vyapar-2/test/cdaci): failed to open dir: Invalid
Windows related issues so blew away my development box and put
Linux on it instead :-) But I digress...
Cheers.
Armando
-Original Message-
From: Mike [mailto:[EMAIL PROTECTED]
Sent: November 29, 2004 11:06 PM
To: 'Pravin-Kumar'; [EMAIL PROTECTED]
Subject: RE: [PHP-WIN] pro
hi mike!
$source='F:\cdac2';
echo $source;
if(is_dir($source)){echo "it is a dir.";}
else{echo "it is not a dir..";}
i had tried ur suggestion .. not working dude :(
see i had one more thing .. it says "it is not a dir.."
please help me list...
--
When you set the $dir variable, try doing so with single quotes - the \
character is used to escape things and might be causing some problems.
If that makes no sense, it's because I'm falling asleep.
Good luck.
-M
> -Original Message-
> From: Pravin-Kumar [mailto:[EMAIL PROTECTED]
> S
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