Matthew,
It seems, from looking at your supplied code, that you have a variable-naming
typographic error.
The variables have to match:
$projects_results = mysql_query($projects, $conn) or die(mysql_error());
$project_data = mysql_fetch_array($project_results))
--
Jeff White is:
[EMAIL PROTECTE
Matt,
You may want to watch out for is sql injection attacks. Just to be on
the safe side consider something like:
$projects = "select name, type, location, date_added from uploads where
user_id = '" . mysql_real_escape_string($_SESSION['user_id'], $conn) .
"'";
The reason for the error is $pro
