ansmission; however, several electrons were
terribly inconvenienced.
- Original Message
From: Mikael Grön <[EMAIL PROTECTED]>
To: [EMAIL PROTECTED]
Sent: Thursday, April 12, 2007 10:41:28 AM
Subject: Re: [PHP-WIN] Calling PHP from PHP
If you're not using an external program or scrip
If you're not using an external program or script to run all your php
scripts, but want one script to execute another, then include or require
are the only methods that'll do the job.
Putting the include / require -part in the end of the first script is
exactly the same as running them both afte
Mikael Grön wrote:
Sidenote:
You can also do:
$dir = "folder/of/include/files";
$files = opendir($dir);
while ($file = readdir($file)):
if (substr($file,-4) == '.php'):
include_once($dir.'/'.$file);
endif;
endwhile;
but I wouldn't recommend it. :P
No neither would I recommend that
Sidenote:
You can also do:
$dir = "folder/of/include/files";
$files = opendir($dir);
while ($file = readdir($file)):
if (substr($file,-4) == '.php'):
include_once($dir.'/'.$file);
endif;
endwhile;
but I wouldn't recommend it. :P
Mike
John Comerford skrev:
Yes, what you have descr
Yes, what you have described should work fine..
sam rumaizan wrote:
1- I have 50 php pages.
2- I want to include all 50 php pages in my main page.
include("1.php"); .. include("50.php");
My question is:
can I put all of the include php pages in one php page and sa
1- I have 50 php pages.
2- I want to include all 50 php pages in my main page.
include("1.php"); .. include("50.php");
My question is:
can I put all of the include php pages in one php page and save it as
includepages.php then include this php page to my main page
includ
Not sure if i understand properly... you don't want to use the include
() function or you don't want to have the code of script B in script A?
If it is the later you can use include("path/to/scriptB.php"); or
require("path/to/scriptB.php");
you can also use include_once() and require_once()
