You forgot to select a database.
mysql_select_db("database",$link_id);
That should work.
> --
> From: paul morgan[SMTP:[EMAIL PROTECTED]]
> Sent: Saturday, March 31, 2001 1:53 AM
> To: [EMAIL PROTECTED]
> Subject: [PHP-WIN] unhappy cam
");
$result = mysql_list_tables ("MYSQL")
or die ("Invalid query");
print ("Connected successfully");
while ($i < mysql_num_rows ($result)) {
$tb_names[$i] = mysql_tablename ($result, $i);
echo $tb_names[$i] . "";
$i++;
}
?>
this is from the php manual
""paul morgan"" <[EMAIL PROT
Warning: Supplied argument is not a valid MySQL result resource in
e:/apache/apache/htdocs/tr.php on line 7
huum this is the error I got. you need to read a bit more mysql
documentation
and perhaps the mysql functions in php.
what data base are you trying to show_tables on ?
""paul morgan"" <[
hi,
I'm new to this game but have managed to set up apache 1.3.19 that runs
php/4.0.4pl1 (the apache dll I think) on Win 98 SE. I've also installed the
windows build of mysql, version 3.23 I think and can administer easily via
the msdos prompt. I have removed the general root user, as in the mysql
