Well, simply put (not really following your structure):
--- code ---
$sql = "update $tablename set address = '$address', phone =
'$phone' where LastName = '$lastname';";
if (mysql_query($sql)):
echo "Updated " . $_POST['R'] . "\n";
else:
echo "Error: " . mysq
I don't get the purpose of your code. It's not looking right anywhere!
I'm guessing the select-box isn't working too well, right?
Let's say there's 4 $lines:
foreach ($line as $value)
{
echo"$value";
will produce:
value='value3'value4
... You need to use this code for the
bedul,
This is what I need (don't worry about the variable names since they are
different from my previous email.)
';
$query = "SELECT Assign_Engineer FROM lodata";
$result = mysql_query($query);
echo"";
echo"";
echo"";
echo"";
echo"Choose Name :
";
while ($line = m
--
From: sam rumaizan [mailto:[EMAIL PROTECTED]
Sent: Tuesday, April 03, 2007 8:00 AM
To: php-windows@lists.php.net
Cc: [EMAIL PROTECTED]
Subject: [PHP-WIN] insert data in to columns base on the selection of
the list box.
Can you help me please?
1- I have created a while loop to populate
EMAIL PROTECTED]
Sent: Tuesday, April 03, 2007 8:00 AM
To: php-windows@lists.php.net
Cc: [EMAIL PROTECTED]
Subject: [PHP-WIN] insert data in to columns base on the selection of
the list box.
Can you help me please?
1-I have created a while loop to populate the list box with the
informa
Can you help me please?
1-I have created a while loop to populate the list box with the
information of column1.
2-I need to update (add data) in to column2, column3, column4 base on
the selection of the list box.
echo'';
$query = "SELECT column1 FROM table";
$re
